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How to produce a range with step n in bash? (generate a sequence of numbers with increments)
...n its own).
Note that seq allows floating-point numbers (e.g., seq .5 .25 3.5) but bash's brace expansion only allows integers.
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What is %2C in a URL?
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623
Check out http://www.asciitable.com/
Look at the Hx, (Hex) column; 2C maps to ,
Any unusual en...
How to check if a string is a valid hex color representation?
... -> match end
i -> ignore case
If you need support for 3-character HEX codes, use the following:
/^#([0-9A-F]{3}){1,2}$/i.test('#ABC')
The only difference here is that
[0-9A-F]{6}
is replaced with
([0-9A-F]{3}){1,2}
This means that instead of matching exactly 6 charact...
Print a list in reverse order with range()?
...parameters. range(start, stop, step)
For example, to generate a list [5,4,3,2,1,0], you can use the following:
range(5, -1, -1)
It may be less intuitive but as the comments mention, this is more efficient and the right usage of range for reversed list.
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Regular expression for matching latitude/longitude coordinates?
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Miha_x64
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answered Aug 19 '10 at 3:38
Eric CEric C
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How do I concatenate two lists in Python?
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You can use the + operator to combine them:
listone = [1,2,3]
listtwo = [4,5,6]
joinedlist = listone + listtwo
Output:
>>> joinedlist
[1,2,3,4,5,6]
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Why would adding a method add an ambiguous call, if it wouldn't be involved in the ambiguity
...orm
1: C(params string[]) in its expanded form
2: C<string>(string)
3: C(string, object)
Candidate zero is obviously inapplicable because string is not convertible to string[]. That leaves three.
Of the three, we must determine a unique best method. We do so by making pairwise comparison...
TCP 的那些事儿（下） - 更多技术 - 清泛网 - 专注C/C++及内核技术
...这只是一个采样，不能代表普遍情况。
经典算法
RFC793 中定义的经典算法是这样的：
1）首先，先采样RTT，记下最近好几次的RTT值。
2）然后做平滑计算SRTT（ Smoothed RTT）。公式为：（其中的 α 取值在0.8 到 0.9之间，这个...
Split a List into smaller lists of N size
...List<float[]>> SplitList(List<float[]> locations, int nSize=30)
{
var list = new List<List<float[]>>();
for (int i = 0; i < locations.Count; i += nSize)
{
list.Add(locations.GetRange(i, Math.Min(nSize, locations.Count - i)));
}
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