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How can I verify if a Windows Service is running

I have an application in C# (2.0 running on XP embedded) that is communicating with a 'watchdog' that is implemented as a Windows Service. When the device boots, this service typically takes some time to start. I'd like to check, from my code, if the service is running. How can I accomplish this? ...
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Why are there two build.gradle files in an Android Studio project?

After having imported an Eclipse project into Android Studio, I see two build.gradle files: 2 Answers ...
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How to do a batch insert in MySQL

I have 1-many number of records that need to be entered into a table. What is the best way to do this in a query? Should I just make a loop and insert one record per iteration? Or is there a better way? ...
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How can I access a JavaScript object which has spaces in the object's key?

I have a JavaScript object that looks something like this: 5 Answers 5 ...
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How to return dictionary keys as a list in Python?

In Python 2.7 , I could get dictionary keys , values , or items as a list: 8 Answers ...
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Removing packages installed with go get

I ran go get package to download a package before learning that I needed to set my GOPATH otherwise that package sullies my root Go install (I would much prefer to keep my Go install clean and separate core from custom). How do I remove packages installed previously? ...
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Time complexity of Sieve of Eratosthenes algorithm

From Wikipedia: 4 Answers 4 ...
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C# - Multiple generic types in one list

This is probably not possible, but I have this class: 3 Answers 3 ...
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How to check if a function exists on a SQL database

I need to find out if a function exists on a database, so that I can drop it and create it again. It should basically be something like the following code that I use for stored procedures: ...
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When to use a “has_many :through” relation in Rails?

I am trying to understand what has_many :through is and when to use it (and how). However, I am not getting it. I am reading Beginning Rails 3 and I tried Googling, but I am not able to understand. ...