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symbol(s) not found for architecture i386
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If you get this sort of thing appearing suddenly, it usually means the project is missing some frameworks it needs. Libraries and dependent projects can require frameworks, so if you've added one recently then that can cause this error.
To add frameworks...
LINQ: Distinct values
...ityComparer<T>
{
private readonly Func<T, T, bool> _expression;
public LambdaComparer(Func<T, T, bool> lambda)
{
_expression = lambda;
}
public bool Equals(T x, T y)
{
return _expression(x, y);
}
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List all files and directories in a directory + subdirectories
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it means that in your system this app hasn't got enough permissions
– Ruslan F.
Sep 8 '12 at 16:44
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Where do I mark a lambda expression async?
...oking for? Browse other questions tagged c# lambda resharper windows-store-apps async-await or ask your own question.
How can I get a java.io.InputStream from a java.lang.String?
... As of java7: new ByteArrayInputStream(str.getBytes(StandardCharsets.UTF_8))
– slow
Jan 17 '14 at 22:25
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Python's json module, converts int dictionary keys to strings
...on they must be immutable types, or they must be objects which implement a __hash__ method. (The Lua docs suggest that it automatically uses the object's ID as a hash/key even for mutable objects and relies on string interning to ensure that equivalent strings map to the same objects).
In Perl, J...
What's the difference between size_t and int in C++?
In several C++ examples I see a use of the type size_t where I would have used a simple int . What's the difference, and why size_t should be better?
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How can I append a string to an existing field in MySQL?
I want to update the code on all my record to what they currently are plus _standard any ideas?
2 Answers
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Creating a new dictionary in Python
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Call dict with no parameters
new_dict = dict()
or simply write
new_dict = {}
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How can I get rid of an “unused variable” warning in Xcode?
...as an "unused" attribute you can use to suppress that warning:
BOOL saved __attribute__((unused)) = [moc save:&error];
Alternatively (in case LLVM doesn't support the above), you could split the variable declaration into a separate line, guaranteeing that the variable would be "used" whether ...