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Is there a “not equal” operator in Python?
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Use !=. See comparison operators. For comparing object identities, you can use the keyword is and its negation is not.
e.g.
1 == 1 # -> True
1 != 1 # -> False
[] is [] #-> False (distinct objects)
a = b = []; a is b # -> True (same object)
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How to convert a string of numbers to an array of numbers?
I have below string -
14 Answers
14
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How can a string be initialized using “ ”?
If String is a class just like any other, how can it be initialized using double quotes?
10 Answers
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How to print like printf in Python3?
...duced a statement:
print "Hi"
In Python3, print is a function which may be invoked:
print ("Hi")
In both versions, % is an operator which requires a string on the left-hand side and a value or a tuple of values or a mapping object (like dict) on the right-hand side.
So, your line ought to loo...
Sort hash by key, return hash in Ruby
Would this be the best way to sort a hash and return Hash object (instead of Array):
10 Answers
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lexers vs parsers
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What parsers and lexers have in common:
They read symbols of some alphabet from their input.
Hint: The alphabet doesn't necessarily have to be of letters. But it
has to be of symbols which are atomic for the language
understood by parser/lexer.
Symbols for the lexer: ASCII ch...
What is the difference between graph search and tree search?
What is the difference between graph search and tree search versions regarding DFS, A* searches in artificial intelligence ?
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Validating IPv4 addresses with regexp
I've been trying to get an efficient regex for IPv4 validation, but without much luck. It seemed at one point I had had it with (25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?(\.|$)){4} , but it produces some strange results:
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Why does C++ not allow inherited friendship?
Why is friendship not at least optionally inheritable in C++? I understand transitivity and reflexivity being forbidden for obvious reasons (I say this only to head off simple FAQ quote answers), but the lack of something along the lines of virtual friend class Foo; puzzles me. Does anyone know ...