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How to capitalize first letter of each word, like a 2-word city? [duplicate]
...Case()
.split(' ')
.map((s) => s.charAt(0).toUpperCase() + s.substring(1))
.join(' ');
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How to keep environment variables when using sudo
...le by a feature of the bash builtin printf. The %q produces a shell quoted string. Unlike the parameter expansion in bash 4.4, this works in bash versions < 4.0
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Jackson enum Serializing and DeSerializer
...rmat {
Weekday,
EvenOdd,
Interval;
private static Map<String, DeviceScheduleFormat> namesMap = new HashMap<String, DeviceScheduleFormat>(3);
static {
namesMap.put("weekday", Weekday);
namesMap.put("even-odd", EvenOdd);
namesMap.put("interval...
Converting a date string to a DateTime object using Joda Time library
I have a date as a string in the following format "04/02/2011 20:27:05" . I am using Joda-Time library and would like to convert it to DateTime object. I did:
...
How do I set the selected item in a comboBox to match my string using C#?
I have a string "test1" and my comboBox contains test1 , test2 , and test3 . How do I set the selected item to "test1"? That is, how do I match my string to one of the comboBox items?
...
Get generic type of class at runtime
...t; of(Class<T> type) {...} and then call it as such: GenericClass<String> var = GenericClass.of(String.class). A bit nicer.
– Joeri Hendrickx
Aug 1 '16 at 20:04
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Cannot convert lambda expression to type 'string' because it is not a delegate type [duplicate]
...t please described on Kendo UI : Cannot convert lambda expression to type 'string' because it is not a delegate type? Thanks in advance.
– Jack
Feb 5 '15 at 14:31
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Getting current device language in iOS?
...tes). In order to retrieve the currently selected language, you can do:
NSString * language = [[NSLocale preferredLanguages] firstObject];
This will return a two letter code for the currently selected language. "en" for English, "es" for Spanish, "de" for German, etc. For more examples, please se...
How do I handle newlines in JSON?
..." : 1, "stack" : "sometext\\n\\n"}';
(You need to escape the "\" in your string (turning it into a double-"\"), otherwise it will become a newline in the JSON source, not the JSON data.)
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Search for a string in Enum and return the Enum
...iteration and realised it wasn't quite right because Enum.GetNames returns strings. You want Enum.GetValues:
public MyColours GetColours(string colour)
{
foreach (MyColours mc in Enum.GetValues(typeof(MyColours)))
if (mc.ToString() == surveySystem)
return mc;
return MyColors.Def...