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Parsing JSON using Json.net
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I don't know about JSON.NET, but it works fine with JavaScriptSerializer from System.Web.Extensions.dll (.NET 3.5 SP1):
using System.Collections.Generic;
using System.Web.Script.Serialization;
public class NameTypePair
{
public string OBJECT_NAME { get; set; }
public ...
jQuery: $().click(fn) vs. $().bind('click',fn);
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Not the answer you're looking for? Browse other questions tagged javascript jquery event-handling or ask your own question.
Bootstrap carousel multiple frames at once
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This is a working twitter bootstrap 3.
Here is the javascript:
$('#myCarousel').carousel({
interval: 10000
})
$('.carousel .item').each(function(){
var next = $(this).next();
if (!next.length) {
next = $(this).siblings(':first');
}
next.childre...
In Firebase, is there a way to get the number of children of a node without loading all the node dat
... Functions, you don't need to create your own Server. You can simply write JavaScript functions and upload it to Firebase. Firebase will be responsible for triggering functions whenever an event occurs.
If you want to count upvotes for example, you should create a structure similar to this one:
{
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What is the method for converting radians to degrees?
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In javascript you can do it this way
radians = degrees * (Math.PI/180);
degrees = radians * (180/Math.PI);
share
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How do I select an element with its name attribute in jQuery? [duplicate]
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how do i remove a comma off the end of a string?
... not all concatenations may take place in PHP. In my case, I am sending a Javascript concatenated string for PHP to unravel.
– Sablefoste
Sep 11 '15 at 19:49
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Re-enabling window.alert in Chrome
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var.replace is not a function
I'm using the below code to try to trim the string in Javascript but am getting the error mentioned in the title:
10 Answer...
How do I initialize a TypeScript object with a JSON object
...other languages where I'm aware of deserialization of any kind. Of course, Javascript won't complain if you call a non-default constructor with no arguments, but the class better be prepared for it then (plus, it wouldn't really be the "typescripty way").
Option #1: No run-time information at all
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