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How can I create a copy of an object in Python?
I would like to create a copy of an object. I want the new object to possess all properties of the old object (values of the fields). But I want to have independent objects. So, if I change values of the fields of the new object, the old object should not be affected by that.
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What's the difference between deadlock and livelock?
Can somebody please explain with examples (of code) what is the difference between deadlock and livelock ?
7 Answers
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Concatenating two std::vectors
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vector1.insert( vector1.end(), vector2.begin(), vector2.end() );
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Git submodule update
I'm not clear on what the following means (from the Git submodule update documentation):
4 Answers
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jQuery: select an element's class and id at the same time?
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Tintin81
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answered Dec 22 '09 at 5:24
cletuscletus
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How to join two sets in one line without using “|”
...edited Jun 26 '17 at 12:03
Rishabh Agrahari
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answered Jul 2 '13 at 15:57
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PostgreSQL return result set as JSON array?
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TL;DR
SELECT json_agg(t) FROM t
for a JSON array of objects, and
SELECT
json_build_object(
'a', json_agg(t.a),
'b', json_agg(t.b)
)
FROM t
for a JSON object of arrays.
List of objects
This section describes how to generate a JSON array of objects, ...
How can I return to a parent activity correctly?
I have 2 activities (A and B) in my android application and I use an intent to get from activity A to activity B. The use of parent_activity is enabled:
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Short form for Java if statement
...me() == null) ? "N/A" : city.getName());
I think you have the conditions backwards - if it's null, you want the value to be "N/A".
What if city is null? Your code *hits the bed in that case. I'd add another check:
name = ((city == null) || (city.getName() == null) ? "N/A" : city.getName());
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gcc warning" 'will be initialized after'
...e warnings from 3rd party code that I cannot modify.
Is there a way to disable this warning or at least disable it for certain areas (like #pragma push/pop in VC++)?
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