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A quick and easy way to join array elements with a separator (the opposite of split) in Java [duplic
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@anoniim Joiner.join in what is now Google Guava is overloaded for Iterable as well as Arrays: docs.guava-libraries.googlecode.com/git-history/release/javadoc/…
– nd.
Nov 28 '13 at 18:48
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@Scope(“prototype”) bean scope not creating new bean
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So we dont have it now in spring 5 ?
– Raghuveer
Mar 8 '19 at 7:47
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Gson: Directly convert String to JsonObject (no POJO)
...tempting JSON tree manipulation in GSON, but I have a case where I do not know or have a POJO to convert a string into, prior to converting to JsonObject . Is there a way to go directly from a String to JsonObject ?
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Function in JavaScript that can be called only once
... executed only once, in each time after the first it won't be executed. I know from C++ and Java about static variables that can do the work but I would like to know if there is a more elegant way to do this?
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PHP abstract properties
...lass Father
{
public $name;
abstract protected function setName(); // now every child class must declare this
// function and thus declare the property
public function __construct()
{
$this->setName();
}
}
class Son extends Father
{
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MD5 algorithm in Objective-C
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Thanks! Patched it up now. This was never a problem for me since in the original implementation, I always ran it in a dedicated thread ;)
– Alexander W
Oct 10 '14 at 8:59
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Best way to track onchange as-you-type in input type=“text”?
...eone.
So onkeyup is better for when you want to send what you just typed now.
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Why does 2 == [2] in JavaScript?
...a[array] it tries to turn the array into a number first, then string. Who knows?
var a = { "abc" : 1 };
a[["abc"]] === a["abc"];
In this example, you are creating an object called a with a member called abc. The right side of the equation is pretty simple; it is equivalent to a.abc. This returns ...
Test if a property is available on a dynamic variable
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Thanks, looks really complete now.
– bland
Nov 15 '13 at 14:08
@dav_i it'...
Watch multiple $scope attributes
...o angular just checks whether the result of the concatenation is different now.
– mb21
Sep 5 '12 at 22:11
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