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demystify Flask app.secret_key
...ts; if you didn't set a server-side secret for the encryption to use, everyone would be able to break your encryption; it's like the password to your computer. The secret plus the data-to-sign are used to create a signature string, a hard-to-recreate value using a cryptographic hashing algorithm; on...
A valid provisioning profile for this executable was not found for debug mode
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It could be because your iphone is not recognized by the provisioning portal.
Solution:
1) In Xcode, Goto --> Build --> clean all targets.
2) In "Groups & Files" -->Target --> expand it --> right click your app and select Clean "yo...
How can I maximize a split window?
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this will close other windows, and if you have one or more windows where you have made changes and not saved, then this will not work - also I think question is about maximizing window to work for a short time in that state and then later on return to previous state -- by...
What are best practices for REST nested resources?
As far as I can tell each individual resource should have only one canonical path. So in the following example what would good URL patterns be?
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How can I create a two dimensional array in JavaScript?
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@AndersonGreen It's a good thing you mentioned a link for those interested in multi-D array solution, but the question and Ballsacian1's answer are about "2D" array, not "multi-D" array
– evilReiko
Jun 14 '14 at 9:56
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What exactly is an HTTP Entity?
Would someone please describe to me what exactly an HTTP entity is?
9 Answers
9
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Get name of object or class
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I was facing a similar difficulty and none of the solutions presented here were optimal for what I was working on. What I had was a series of functions to display content in a modal and I was trying to refactor it under a single object definition making the functi...
Javascript: negative lookbehind equivalent?
... + iPadOS)
❌ Chakra: Microsoft was working on it but Chakra is now abandoned in favor of V8
❌ Internet Explorer
❌ Edge versions prior to 79 (the ones based on EdgeHTML+Chakra)
share
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imp...
How can I multiply and divide using only bit shifting and adding?
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To multiply in terms of adding and shifting you want to decompose one of the numbers by powers of two, like so:
21 * 5 = 10101_2 * 101_2 (Initial step)
= 10101_2 * (1 * 2^2 + 0 * 2^1 + 1 * 2^0)
= 10101_2 * 2^2 + 10101_2 * 2^0
= 10101_2 << 2 + 101...
How to overwrite the previous print to stdout in python?
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One way is to use the carriage return ('\r') character to return to the start of the line without advancing to the next line:
for x in range(10):
print '{0}\r'.format(x),
print
The comma at the end of the print statement...