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Bamboo Vs. Hudson(a.k.a. Jenkins) vs Any other CI systems [closed]
...lso, this maybe pie in the sky, but is there something that can also build IPhone apps?
Similar to the answer to your first question, most CI servers will be able to build iPhone apps in some ways. It's possible that there is a little more scripting required though.
Price: Bamboo is not free(apa...
iOS 7 status bar back to iOS 6 default style in iPhone app?
In iOS 7 the UIStatusBar has been designed in a way that it merges with the view like this:
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社会化海量数据采集爬虫框架搭建 - 大数据 & AI - 清泛网 - 专注C/C++及内核技术
...看到都应该能采集到。所见即所得的无阻拦式采集，无论是否需要登录的数据都能够顺利采集。现在大部分社交网站都需要登录，为了应对登录的网站要有模拟用户登录的爬虫系统，才能正常获取数据。不过社会化网站都希望自...
Is it possible to get the iOS 5.1 SDK for Xcode 4.2 on Snow Leopard?
... Leopard. I have Xcode 4.2 for iOS development. This morning I upgraded my iPhone and iPad to iOS 5.1.
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How to use UIScrollView in Storyboard
...he frame attribute. Indeed, all devices does not have the exact same size (iPhone 5).
– Tronix117
Aug 22 '13 at 15:43
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iOS Simulator failed to install the application
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Solved the problem
Deleting contents of ~/Library/Application Support/iPhone Simulator and re-run the project solved this problem.
or you can simply reset content and setting of the simulator.
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Find the number of downloads for a particular app in apple appstore [closed]
...you numbers that you can guess off of! They have numbers for Android, iOS (iPhone and iPad) and even Windows!
xyo.net
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Virtual functions and performance - C++
...bjective-C (where all methods are virtual) is the primary language for the iPhone and freakin' Java is the main language for Android, I think it's pretty safe to use C++ virtual functions on our 3 GHz dual-core towers.
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C++实现一款简单完整的聊天室服务器+客户端 - C/C++ - 清泛网 - 专注C/C++及内核技术
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运行服务器
./server 8000
注意Linux下的防火墙iptables服务是否已经启动，如果启动了，需要在/etc/sysconfig/iptables中加入例外端口8000，并重启启动防火墙
/etc/init.d/iptables restart
基于WSAAsyncSelect模型实现的聊天室图形客户端
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栈和队列的面试题Java实现 - 更多技术 - 清泛网 - 专注C/C++及内核技术
...h、pop、的时间复杂度都是O(1)
（6）判断栈的push和pop序列是否一致
1、栈的创建：
我们接下来通过链表的形式来创建栈，方便扩充。
代码实现：
public class Stack {
public Node head;
public Node current;
//方法：入栈操作
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