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jQuery: more than one handler for same event

...ous places without actually .off it anywher? – techie_28 May 24 '16 at 9:01 Note that for jQueryUI widgetfactory widge...
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Two-dimensional array in Swift

...ass]] = [] for i in 0...23 { matrix.append( [] ) for _ in 0...79 { matrix[i].append( MyClass() ) } } return matrix } share | improve this answer ...
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What is “Orthogonality”?

...is sense of "orthogonal" is covered by: en.wikipedia.org/wiki/Orthogonality_(programming) , but it's a new page with little content. – outis Oct 24 '09 at 11:33 1 ...
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If my interface must return Task what is the best way to have a no-operation implementation?

...d May 30 '19 at 20:01 trashmaker_trashmaker_ 10111 silver badge22 bronze badges
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Globally override key binding in Emacs

...fter-load-functions 'my-keys-have-priority) (defun my-keys-have-priority (_file) "Try to ensure that my keybindings retain priority over other minor modes. Called via the `after-load-functions' special hook." (unless (eq (caar minor-mode-map-alist) 'my-keys-minor-mode) (let ((mykeys (assq ...
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What is the meaning of “$” sign in JavaScript

...identifier. JavaScript allows upper and lower letters, numbers, and $ and _. The $ was intended to be used for machine-generated variables (such as $0001). Prototype, jQuery, and most javascript libraries use the $ as the primary base object (or function). Most of them also have a way to relinquis...
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Error :: duplicate files during packaging of APK

...nswered May 1 '15 at 22:58 Pian0_M4nPian0_M4n 2,1122525 silver badges3131 bronze badges ...
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Can an Android NFC phone act as an NFC tag?

...nswered Nov 2 '13 at 13:53 iglen_iglen_ 17122 silver badges99 bronze badges ...
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Escaping HTML strings with jQuery

...ute; Here's a list of html entities, for reference : w3schools.com/tags/ref_entities.asp – LoganWolfer Apr 1 '11 at 21:50 11 ...
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How to generate all permutations of a list?

...approach, taken from http://code.activestate.com/recipes/252178/: def all_perms(elements): if len(elements) <=1: yield elements else: for perm in all_perms(elements[1:]): for i in range(len(elements)): # nb elements[0:1] works in both string a...