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read file from assets
....txt")));
// do reading, usually loop until end of file reading
String mLine;
while ((mLine = reader.readLine()) != null) {
//process line
...
}
} catch (IOException e) {
//log the exception
} finally {
if (reader != null) {
try {
reader...
Javascript Array of Functions
...u want to execute a given function in the array:
array_of_functions[0]('a string');
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What is an idiomatic way of representing enums in Go?
...
A very simple way to create an object that starts to look and feel like a string enum in Python would be:
package main
import (
"fmt"
)
var Colors = newColorRegistry()
func newColorRegistry() *colorRegistry {
return &colorRegistry{
Red: "red",
Green: "green",
...
Remove multiple whitespaces
..., how we can keep \n and remove all other multiple space and tabs from the string? please help me
– Mansoorkhan Cherupuzha
Sep 20 '13 at 9:20
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read complete file without using loop in java
...byte[] data = new byte[(int) file.length()];
fis.read(data);
fis.close();
String str = new String(data, "UTF-8");
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How to send a simple string between two programs using pipes?
...********/
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <unistd.h>
#include <sys/types.h>
int main(void)
{
int fd[2], nbytes;
pid_t childpid;
char string[] = "Hello, world!\n";
char readbuffer[80];
...
Ruby function to remove all white spaces?
...ex removing all characters which would constitute whitespace rather than a string of delete() calls.)
– Ed S.
Oct 4 '12 at 21:49
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Tuples( or arrays ) as Dictionary keys in C#
...ctionary lookup table in C#. I need to resolve a 3-tuple of values to one string. I tried using arrays as keys, but that did not work, and I don't know what else to do. At this point I am considering making a Dictionary of Dictionaries of Dictionaries, but that would probably not be very pretty t...
How does one create an InputStream from a String? [duplicate]
...to working with streams in Java - how do I create an InputStream from a String ?
6 Answers
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How to test if list element exists?
...tain NULL elements, it might not be enough to check is.null(foo$a). A more stringent test might be to check that the name is actually defined in the list:
foo <- list(a=42, b=NULL)
foo
is.null(foo[["a"]]) # FALSE
is.null(foo[["b"]]) # TRUE, but the element "exists"...
is.null(foo[["c"]]) # TRUE...