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How do I get the base URL with PHP?
...defined variable.
If you plan on using https, you can use this:
function url(){
return sprintf(
"%s://%s%s",
isset($_SERVER['HTTPS']) && $_SERVER['HTTPS'] != 'off' ? 'https' : 'http',
$_SERVER['SERVER_NAME'],
$_SERVER['REQUEST_URI']
);
}
echo url();
#=> http://127.0...
Getting Django admin url for an object
Before Django 1.0 there was an easy way to get the admin url of an object, and I had written a small filter that I'd use like this: <a href="{{ object|admin_url }}" .... > ... </a>
...
How can I determine the URL that a local Git repository was originally cloned from?
...
If you want only the remote URL, or if your are not connected to a network that can reach the remote repo:
git config --get remote.origin.url
If you require full output and you are on a network that can reach the remote repo where the origin resides ...
Django URL Redirect
How can I redirect traffic that doesn't match any of my other URLs back to the home page?
5 Answers
...
Save image from URL by paperclip
Please suggest me a way to save an image from an URL by Paperclip.
8 Answers
8
...
URL encoding in Android
How do you encode a URL in Android?
7 Answers
7
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How do short URLs services work?
How do services like TinyURL or Metamark work?
Do they simply associate the tiny URL key with a [virtual?] web page which merely provide an "HTTP redirect" to the original URL? or is there more "magic" to it ?
...
Best way to make Django's login_required the default
...ware component that wraps the login_required decorator around
matching URL patterns. To use, add the class to MIDDLEWARE_CLASSES and
define LOGIN_REQUIRED_URLS and LOGIN_REQUIRED_URLS_EXCEPTIONS in your
settings.py. For example:
------
LOGIN_REQUIRED_URLS = (
r'/topsecret...
Rails: What's a good way to validate links (URLs)?
I was wondering how I would best validate URLs in Rails. I was thinking of using a regular expression, but am not sure if this is the best practice.
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How to launch Safari and open URL from iOS app
...DaleDietrichDotCom:(id)sender {
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:@"http://www.daledietrich.com"]];
}
Swift
(IBAction in viewController, rather than header file)
if let link = URL(string: "https://yoursite.com") {
UIApplication.shared.open(link)
}
...