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html5 - canvas element - Multiple layers
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If you have heavier images, this will take some time to convert HTML to canvas, we had to move away from this just because the rendering took long time.
– Vilius
Sep 27 '17 at 15:36
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JS: Check if date is less than 1 hour ago?
... do it as follows:
First find difference of two dates i-e in milliseconds
Convert milliseconds into minutes
If minutes are less than 60, then it means date is within hour else not within hour.
var date = new Date("2020-07-12 11:30:10");
var now = new Date();
var diffInMS = now - date;
var msInHour...
Show and hide a View with a slide up/down animation
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With the new animation API that was introduced in Android 3.0 (Honeycomb) it is very simple to create such animations.
Sliding a View down by a distance:
view.animate().translationY(distance);
You can later slide the View back to its original position like ...
Recursive directory listing in DOS
...ptions offered by FINDSTR. You can also use the excellent unxutils, but it converts the output to UNIX by default, so you no longer get CR+LF; FINDSTR offers the best Windows option.
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How to select bottom most rows?
...t think it's worth ordering the entire table by a column when you are just interested in the bottom few rows.
– steadyfish
Oct 13 '14 at 16:09
1
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How to check if a string contains a substring in Bash
...independent (Bash only!)
For testing strings without care of case, simply convert each string to lower case:
stringContain() {
local _lc=${2,,}
[ -z "$1" ] || { [ -z "${_lc##*${1,,}*}" ] && [ -n "$2" ] ;} ;}
Check:
stringContain 'o "M3' 'echo "my string"' && echo yes || ...
How to create a GUID/UUID in Python
...t; x = uuid.UUID('{00010203-0405-0607-0809-0a0b0c0d0e0f}')
>>> # convert a UUID to a string of hex digits in standard form
>>> str(x)
'00010203-0405-0607-0809-0a0b0c0d0e0f'
>>> # get the raw 16 bytes of the UUID
>>> x.bytes
'\x00\x01\x02\x03\x04\x05\x06\x07\x08\...
How to use subprocess popen Python
...s.popen is being replaced by subprocess.popen, I was wondering how would I convert
3 Answers
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How to remove items from a list while iterating?
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list(somelist) will convert an iterable into a list. somelist[:] makes a copy of an object that supports slicing. So they don't necessarily do the same thing. In this case I want to make a copy of the somelistobject, so I use [:]
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Check if a string is a date value
.../ You want to check again for !isNaN(parsedDate) here because Dates can be converted
// to numbers, but a failed Date parse will not.
if (isNaN(date) && !isNaN(parsedDate)) {
/* do your work */
}
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