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Git flow release branches and tags - with or without “v” prefix
...reference, but I prefer the version with the v, as Semver does it that way and I try to follow that specification as close as possible to get a sane versioning.
It also makes filtering for those Tags easier, as you can press v and then the TAB-key for autocompletion: This will list all the tags (a...
Select second last element with css
... this answer will work perfectly. Honestly, if people are still using IE 8 and below, they don't deserve to have pretty things.
– Stender
Jan 4 '18 at 13:47
add a comment
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Invalid date format specification in gemspec
I am getting the following error when I try to use gems in windows, and I also referred to
this stackoverflow post and updated rubygems and rails. But nothing could solve the problem.
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Python creating a dictionary of lists
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Oh. This is great. And you don't have to initialize to '= []'. Good stuff!
– Wilmer E. Henao
Dec 7 '17 at 23:16
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PHP foreach loop key value
... postfix: "",
imageUploader: {
brandingHtml: "Powered by \u003ca href=\"https://imgur.com/\"\u003e\u003csvg class=\"svg-icon\" width=\"50\" height=\"18\" viewBox=\"0 0 50 18\" fill=\"none\" xmlns=\"http://www.w3.org/2000/svg\"\u003e\u003cpath d=\"M46.1709 9....
How to extract a git subdirectory and make a submodule out of it?
I started a project some months ago and stored everything within a main directory.
In my main directory "Project" there are several subdirectories containing different things:
Project/paper contains a document written in LaTeX
Project/sourcecode/RailsApp contains my rails app.
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Regular expression for exact match of a string
... passwords with regular expression. For example I have two inputs "123456" and "1234567" then the result should be not match (false). And when I have entered "123456" and "123456" then the result should be match (true).
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Format Instant to String
I'm trying to format an Instant to a String using the new java 8 time-api and a pattern:
7 Answers
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Passing a list of kwargs?
...e: (newlines don't seem to be allowed in comments) def a(**kw): print(kw), and def b(**kw): a(kw). This code will generate an error because kwargs is actually a dictionary, and will be interpreted as a regular argument of the dict type. Which is why changing def b(**kw): a(kw) to def b(**kw): a(**kw...
Extract a substring from a string in Ruby using a regular expression
...which, for each <item> in String1 contains the text between the < and the > in a one-element array (because when used with a regex containing capturing groups, scan creates an array containing the captures for each match). last gives you the last of those arrays and first then gives you ...