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How do I pass JavaScript variables to PHP?

...larieids">SalarieID:</label> <?php $query = "SELECT * FROM salarie"; $result = mysql_query($query); if ($result) : ?> <select id="salarieids" name="salarieid"> <?php while ($row = mysql_fetch_assoc($r...
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How to escape apostrophe (') in MySql?

... Here's an example: SELECT * FROM pubs WHERE name LIKE "%John's%" Just use double quotes to enclose the single quote. If you insist in using single quotes (and the need to escape the character): SELECT * FROM pubs WHERE name LIKE '%John\'s%'...
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MySQL DISTINCT on a GROUP_CONCAT()

I am doing SELECT GROUP_CONCAT(categories SEPARATOR ' ') FROM table . Sample data below: 6 Answers ...
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C#操作XML小结 - 更多技术 - 清泛网 - 专注C/C++及内核技术

...Server.MapPath("~/file/bookstore.xml")); 二、具体实例 在C#.net中如何操作XML需要添加的命名空间: using System.Xml; 定义几个公共对象: XmlDocument xmldoc; XmlNode xmlnode; XmlElement xmlelem; 1,创建到服务器同名目录下的xml文件: 方法一: ...
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How to get a float result by dividing two integer values using T-SQL?

...s or parameters which are integers, you can cast them to be floats first: SELECT CAST(1 AS float) / CAST(3 AS float) or SELECT CAST(MyIntField1 AS float) / CAST(MyIntField2 AS float) share | i...
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C++ protobuf使用入门实例 - C/C++ - 清泛网 - 专注C/C++及内核技术

...singleton enumeration to represent the null value for the // `Value` type union. // // The JSON representation for `NullValue` is JSON `null`. enum TestNullValue { // Null value. NULL_VALUE = 0; } // `ListValue` is a wrapper around a repeated field of values. // // The JSON represen...
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What are the best PHP input sanitizing functions?

... much more thorough job of both stripping out all HTML and also allowing a selective whitelist of tags and attributes through. Modern PHP versions ship with the filter extension, which provides a comprehensive way to sanitize user input. Validation Making sure that submitted data is free from unexpe...
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How to add new column to MYSQL table?

...r comment it looks like your'e only adding the new column if: mysql_query("SELECT * FROM assessment"); returns false. That's probably not what you wanted. Try removing the '!' on front of $sql in the first 'if' statement. So your code will look like: $sql=mysql_query("SELECT * FROM assessment"); if...
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LIMIT 10..20 in SQL Server

... For SQL Server 2012 + you can use. SELECT * FROM sys.databases ORDER BY name OFFSET 5 ROWS FETCH NEXT 5 ROWS ONLY share | improve this answer ...
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mysql create user if not exists

... I use SELECT EXISTS (SELECT DISTINCT user FROM mysql.user WHERE user = "username") as is_user should return 1 if exists or 0 if it does not share ...