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NodeJS: How to decode base64 encoded string back to binary? [duplicate]
...hod should instead be used to construct a new buffer from a base64 encoded string:
var b64string = /* whatever */;
var buf = Buffer.from(b64string, 'base64'); // Ta-da
For Node.js v5.11.1 and below
Construct a new Buffer and pass 'base64' as the second argument:
var b64string = /* whatever */;
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How does this code generate the map of India?
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The long string is simply a binary sequence converted to ASCII. The first for statement makes b start out at 10, and the [b+++21] after the string yields 31. Treating the string as an array, offset 31 is the start of the "real" data...
How to read a text file reversely with iterator in C#
...lt;/summary>
public sealed class ReverseLineReader : IEnumerable<string>
{
/// <summary>
/// Buffer size to use by default. Classes with internal access can specify
/// a different buffer size - this is useful for testing.
/// </summary>
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C++ convert from 1 char to string? [closed]
I need to cast only 1 char to string . The opposite way is pretty simple like str[0] .
2 Answers
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How to use hex color values
... a combination of the previous methods. There is absolutely no need to use strings.
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c#: getter/setter
...at it meant. I know they are getters and setters, but want to know why the string Type is defined like this. Thanks for helping me.
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Why does ('0' ? 'a' : 'b') behave different than ('0' == true ? 'a' : 'b') [duplicate]
...for completeness:
('0' ? 'a' : 'b')
is 'a', because '0' is a non-empty string, which always evaluates to true:
String: The result is false if the argument is the empty String (its length is zero);
otherwise the result is true.
Now to '0' == true.
Two type conversions will take place h...
Adding two numbers concatenates them instead of calculating the sum
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They are actually strings, not numbers. The easiest way to produce a number from a string is to prepend it with +:
var x = +y + +z;
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How to print VARCHAR(MAX) using Print Statement?
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I used print(substring(@script, @Counter * 8000, (@Counter + 1) * 8000)) to print my script.
– Lukas Thum
Oct 9 '18 at 12:24
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How can I include raw JSON in an object using Jackson?
... type as 'java.lang.Object', since this should work ok: for serialization, String will be output as is, and for deserialization, it will be deserialized as a Map. Actually you might want to have separate getter/setter if so; getter would return String for serialization (and needs @JsonRawValue); and...