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disable textbox using jquery?
...putting this answer for people who would see the question afterwards.
The best way to change the state in JQuery now is through
$("#input").prop('disabled', true);
$("#input").prop('disabled', false);
Please check this link for full illustration.
Disable/enable an input with jQuery?
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How to use SharedPreferences in Android to store, fetch and edit values [closed]
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I like this answer the best because it uses getDefaultSharedPreferences. For most users this will simplify things because the same preferences can be accessed throughout the entire app and you don't have to worry about naming your preferences file....
Handling applicationDidBecomeActive - “How can a view controller respond to the app becoming Active?
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Best place to put removeObserver in Swift: deinit method.
– Enrico Susatyo
May 16 '16 at 7:29
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Prevent double curly brace notation from displaying momentarily before angular.js compiles/interpola
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To avoid the raw Angular HTML code, is ngCloak widespread/best practice? It seems like a no brainer, but I'm not experienced in AngularJS.
– Kevin Meredith
Jan 3 '14 at 2:34
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Building vs. Compiling (Java)
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So as you can see, compiling is only a (small) part of the build (and the best practice is to fully automate all the steps with tools like Maven or Ant and to run the build continuously which is known as Continuous Integration).
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How to make an enum conform to a protocol in Swift?
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I think this approach is probably the best one of the bunch. Quick update is that the simpleDescription should return self.rawValue
– Justin Levi Winter
Nov 4 '14 at 3:30
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How to launch jQuery Fancybox on page load?
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The best way I've found is:
<script type="text/javascript">
$(document).ready(function() {
$.fancybox(
$("#WRAPPER_FOR_hidden_div_with_content_to_show").html(), //fancybox works perfect with hidden...
How to run `rails generate scaffold` when the model already exists?
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wow, one of the best answers i've ever gotten to a programming question. thanks!
– Lan
Dec 2 '10 at 9:45
12
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How can I make console.log show the current state of an object?
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Vanilla JS:
@evan's answer seems best here. Just (ab)use JSON.parse/stringify to effectively make a copy of the object.
console.log(JSON.parse(JSON.stringify(test)));
JQuery specific solution:
You can create a snapshot of an object at a certain point in ...
How to remove .html from URL?
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I think this is the best and most complete answer, thanks!
– ctekk
Nov 26 '17 at 11:09
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