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SyntaxError: Use of const in strict mode
I'm working with node.js, and in one of my js files I'm using const in "strict mode" . When trying to run it, I'm getting an error:
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Named string formatting in C#
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There is no built-in method for handling this.
Here's one method
string myString = "{foo} is {bar} and {yadi} is {yada}".Inject(o);
Here's another
Status.Text = "{UserName} last logged in at {LastLoginDate}".FormatWith(user);
A third improved method p...
MySQL - Get row number on select
Can I run a select statement and get the row number if the items are sorted?
5 Answers
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Convert SQLITE SQL dump file to POSTGRESQL
...n POSTGRESQL. I just updated my local database with a huge amount of data and need to transfer a specific table to the production database.
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Passing arrays as url parameter
...am%5B1%5D=4&aParam%5Ba%5D=b&aParam%5Bc%5D=d"
http_build_query() handles all the necessary escaping for you (%5B => [ and %5D => ]), so this string is equal to aParam[0]=1&aParam[1]=4&aParam[a]=b&aParam[c]=d.
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Generate random numbers using C++11 random library
As the title suggests, I am trying to figure out a way of generating random numbers using the new C++11 <random> library. I have tried it with this code:
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INSTALL_FAILED_NO_MATCHING_ABIS when install apk
I tried to install my app into Android L Preview Intel Atom Virtual Device, it failed with error:
24 Answers
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How to get the primary IP address of the local machine on Linux and OS X? [closed]
I am looking for a command line solution that would return me the primary (first) IP address of the localhost, other than 127.0.0.1
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What is the difference between mutex and critical section?
... between the two of them. On my system for 1,000,000 uncontended acquires and releases, a mutex takes over one second. A critical section takes ~50 ms for 1,000,000 acquires.
Here's the test code, I ran this and got similar results if mutex is first or second, so we aren't seeing any other effect...
How to find duplicates in 2 columns not 1
...composite key between the two fields. This will require a unique stone_id and upcharge_title for each row.
As far as finding the existing duplicates try this:
select stone_id,
upcharge_title,
count(*)
from your_table
group by stone_id,
upcharge_title
having coun...
