大约有 45,000 项符合查询结果（耗时：0.0539秒） [XML]
浮点数在内存中的表示 - C/C++ - 清泛网 - 专注C++内核技术
...\n", f1);
// 0 10000101 11110110000000000000000
void * p = (void *)0x42fb0000;
memcpy(&f1, &p, 4);
printf("%f\n", f1);
// 1 11111111 00000000000000000000000
p = (void *)0xff800000;
memcpy(&f1, &p, 4);
printf("%f\n", f1);
return 0;
}
运行结果：
好了，就写到...
浮点数在内存中的表示 - C/C++ - 清泛网 - 专注C++内核技术
...\n", f1);
// 0 10000101 11110110000000000000000
void * p = (void *)0x42fb0000;
memcpy(&f1, &p, 4);
printf("%f\n", f1);
// 1 11111111 00000000000000000000000
p = (void *)0xff800000;
memcpy(&f1, &p, 4);
printf("%f\n", f1);
return 0;
}
运行结果：
好了，就写到...
浮点数在内存中的表示 - C/C++ - 清泛网 - 专注C++内核技术
...\n", f1);
// 0 10000101 11110110000000000000000
void * p = (void *)0x42fb0000;
memcpy(&f1, &p, 4);
printf("%f\n", f1);
// 1 11111111 00000000000000000000000
p = (void *)0xff800000;
memcpy(&f1, &p, 4);
printf("%f\n", f1);
return 0;
}
运行结果：
好了，就写到...
浮点数在内存中的表示 - C/C++ - 清泛网 - 专注C++内核技术
...\n", f1);
// 0 10000101 11110110000000000000000
void * p = (void *)0x42fb0000;
memcpy(&f1, &p, 4);
printf("%f\n", f1);
// 1 11111111 00000000000000000000000
p = (void *)0xff800000;
memcpy(&f1, &p, 4);
printf("%f\n", f1);
return 0;
}
运行结果：
好了，就写到...
浮点数在内存中的表示 - C/C++ - 清泛网 - 专注C++内核技术
...\n", f1);
// 0 10000101 11110110000000000000000
void * p = (void *)0x42fb0000;
memcpy(&f1, &p, 4);
printf("%f\n", f1);
// 1 11111111 00000000000000000000000
p = (void *)0xff800000;
memcpy(&f1, &p, 4);
printf("%f\n", f1);
return 0;
}
运行结果：
好了，就写到...
浮点数在内存中的表示 - C/C++ - 清泛网 - 专注C++内核技术
...\n", f1);
// 0 10000101 11110110000000000000000
void * p = (void *)0x42fb0000;
memcpy(&f1, &p, 4);
printf("%f\n", f1);
// 1 11111111 00000000000000000000000
p = (void *)0xff800000;
memcpy(&f1, &p, 4);
printf("%f\n", f1);
return 0;
}
运行结果：
好了，就写到...
浮点数在内存中的表示 - C/C++ - 清泛网移动版 - 专注C++内核技术
...\n", f1);
// 0 10000101 11110110000000000000000
void * p = (void *)0x42fb0000;
memcpy(&f1, &p, 4);
printf("%f\n", f1);
// 1 11111111 00000000000000000000000
p = (void *)0xff800000;
memcpy(&f1, &p, 4);
printf("%f\n", f1);
return 0;
}
运行结果：
好了，就写到...
How does the Windows Command Interpreter (CMD.EXE) parse scripts?
I ran into ss64.com which provides good help regarding how to write batch scripts that the Windows Command Interpreter will run.
...
Circle line-segment collision detection algorithm?
... b = 2*f.Dot( d ) ;
float c = f.Dot( f ) - r*r ;
float discriminant = b*b-4*a*c;
if( discriminant < 0 )
{
// no intersection
}
else
{
// ray didn't totally miss sphere,
// so there is a solution to
// the equation.
discriminant = sqrt( discriminant );
// either solution may be on o...
What are the rules for evaluation order in Java?
...
answered Jul 23 '11 at 15:34
Eric LippertEric Lippert
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