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How to convert strings into integers in Python?
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T3=[]
for i in range(0,len(T1)):
T3.append([])
for j in range(0,len(T1[i])):
b=int(T1[i][j])
T3[i].append(b)
print T3
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How do you check whether a number is divisible by another number (Python)?
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This code appears to do what you are asking for.
for value in range(1,1000):
if value % 3 == 0 or value % 5 == 0:
print(value)
Or something like
for value in range(1,1000):
if value % 3 == 0 or value % 5 == 0:
some_list.append(value)
Or any number of things....
Uncaught TypeError: Cannot read property 'msie' of undefined - jQuery tools
...endation for a replacement library? Something with a scroller, overlay and range input slider? I avoid jQuery mobile because it comes pre-styled. I have styled it before and it's a nightmare.
– inorganik
Mar 18 '13 at 15:56
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Check if character is number?
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You could use comparison operators to see if it is in the range of digit characters:
var c = justPrices[i].substr(commapos+2,1);
if (c >= '0' && c <= '9') {
// it is a number
} else {
// it isn't
}
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How can I convert a hex string to a byte array? [duplicate]
...public static byte[] StringToByteArray(string hex) {
return Enumerable.Range(0, hex.Length)
.Where(x => x % 2 == 0)
.Select(x => Convert.ToByte(hex.Substring(x, 2), 16))
.ToArray();
}
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Convert base-2 binary number string to int
...bda x,y : x + y
reduce(add, [int(x) * 2 ** y for x, y in zip(list(binstr), range(len(binstr) - 1, -1, -1))])
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Quickest way to convert a base 10 number to any base in .NET?
...-Z)
string hexavigesimal = IntToString(42,
Enumerable.Range('A', 26).Select(x => (char)x).ToArray());
// convert to sexagesimal
string xx = IntToString(42,
new char[] { '0','1','2','3','4','5','6','7','8','9',
'A','B','C','D','E','F',...
how to return index of a sorted list? [duplicate]
...index array instead.
>>> s = [2, 3, 1, 4, 5]
>>> sorted(range(len(s)), key=lambda k: s[k])
[2, 0, 1, 3, 4]
>>>
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StringLength vs MaxLength attributes ASP.NET MVC with Entity Framework EF Code First
...t to note down is in MaxLength attribute you can only provide max required range not a min required range.
While in StringLength you can provide both.
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Java equivalent of unsigned long long?
...g(objScannerInstance.next("\\d+")); Not exactly elegant because it lacks a range check, but it would let you pull in long numeric inputs that would otherwise possible exceed the range of a signed long. (Leverages the fact that Scanner::next(...) can also accept either a Pattern object or String patt...