大约有 41,000 项符合查询结果(耗时:0.0586秒) [XML]

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Transposing a 2D-array in JavaScript

I've got an array of arrays, something like: 23 Answers 23 ...
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What encoding/code page is cmd.exe using?

When I open cmd.exe in Windows, what encoding is it using? 6 Answers 6 ...
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Incrementing in C++ - When to use x++ or ++x?

I'm currently learning C++ and I've learned about the incrementation a while ago. I know that you can use "++x" to make the incrementation before and "x++" to do it after. ...
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Going from a framework to no-framework [closed]

I've been developing in PHP for about 8 years as a hobby. In 2009, I picked up codeigniter and since then I've not managed to get a single project developed. ...
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Pythonic way to check if a list is sorted or not

Is there a pythonic way to check if a list is already sorted in ASC or DESC 23 Answers ...
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Renew Provisioning Profile

Just got a notice that the provisioning profile for one of my apps is about to expire. Is there some way I can renew the existing one or must I recreate a new one? ...
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Looping through array and removing items, without breaking for loop

I have the following for loop, and when I use splice() to remove an item, I then get that 'seconds' is undefined. I could check if it's undefined, but I feel there's probably a more elegant way to do this. The desire is to simply delete an item and keep on going. ...
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How to break nested loops in JavaScript? [duplicate]

I tried this: 15 Answers 15 ...
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How to handle initializing and rendering subviews in Backbone.js?

I have three different ways to initialize and render a view and its subviews, and each one of them has different problems. I'm curious to know if there is a better way that solves all of the problems: ...
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Algorithm to generate all possible permutations of a list?

Say I have a list of n elements, I know there are n! possible ways to order these elements. What is an algorithm to generate all possible orderings of this list? Example, I have list [a, b, c]. The algorithm would return [[a, b, c], [a, c, b,], [b, a, c], [b, c, a], [c, a, b], [c, b, a]]. ...