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Wildcards in jQuery selectors
I'm trying to use a wildcard to get the id of all the elements whose id begin with "jander". I tried $('#jander*') , $('#jander%') but it doesn't work..
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How do I select an element in jQuery by using a variable for the ID?
For example, the following selects a division with id="2":
6 Answers
6
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Can you pass parameters to an AngularJS controller on creation?
...n API to update properties of a user, name, email, etc. Each user has an 'id' which is passed from the server when the profile page is viewed.
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Find the index of a dict within a list, by matching the dict's value
... name (using a dictionary), this way get operations would be O(1) time. An idea:
def build_dict(seq, key):
return dict((d[key], dict(d, index=index)) for (index, d) in enumerate(seq))
info_by_name = build_dict(lst, key="name")
tom_info = info_by_name.get("Tom")
# {'index': 1, 'id': '2345', 'na...
Proper way to return JSON using node or Express
...": "sqswqswqs",
"timestamp": "2019-11-29T12:46:21.633Z",
"_id": "5de1131d8f7be5395080f7b9",
"name": "topics test xqxq",
"thumbnail": "waterfall-or-agile-inforgraphics-thumbnail-1575031579309.jpg",
"category_id": "5de0fe0b4f76c22ebce2b70a",
"__v": 0
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.Contains() on a list of custom class objects
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You need to implement IEquatable or override Equals() and GetHashCode()
For example:
public class CartProduct : IEquatable<CartProduct>
{
public Int32 ID;
public String Name;
public Int32 Number;
public Decimal CurrentPrice;
public CartP...
Right Align button in horizontal LinearLayout
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Use below code for that
<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="fill_parent"
android:layout_height="wrap_content"
android:layout_marginTop="35dp"
android:orientation="horizontal" >
<TextView
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jquery IDs with spaces
Does anyone know how to select an item in the DOM by ID with jQuery, when that ID has a space?
11 Answers
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Drop a temporary table if it exists
... IF EXISTS ##CLIENTS_KEYWORD
On previous versions you can use
IF OBJECT_ID('tempdb..##CLIENTS_KEYWORD', 'U') IS NOT NULL
/*Then it exists*/
DROP TABLE ##CLIENTS_KEYWORD
CREATE TABLE ##CLIENTS_KEYWORD
(
client_id INT
)
You could also consider truncating the table instead rather than dropping ...
Combine two ActiveRecord::Relation objects
...ates being able to use any ActiveRecord methods on them afterwards, but I didn't need to. I did this:
name_relation = first_name_relation + last_name_relation
Ruby 1.9, rails 3.2
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