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Convert string to symbol-able in ruby
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@Zack .to_s and .humanize should do the job unless you need to preserve full capitalization.
– Tyler Diaz
Sep 18 '15 at 10:00
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Find the day of a week
... +1 Is there a way to use weekdays to get the number of weekday as you do using as.POSIXlt??
– Shambho
Jun 4 '14 at 17:40
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Change cursor to hand when mouse goes over a row in table
How do I change the cursor pointer to hand when my mouse goes over a <tr> in a <table>
11 Answers
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Put content in HttpResponseMessage object?
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It automatically works with the content types so you can do xml/json without extra code
– user755404
Apr 13 '16 at 10:08
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Print a list of all installed node.js modules
...t all node.js modules (installed using npm) to the command line. How can I do this?
7 Answers
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Is there a way to make mv create the directory to be moved to if it doesn't exist?
...ectory and I want to move foo.c to ~/bar/baz/foo.c , but those directories don't exist, is there some way to have those directories automatically created, so that you would only have to type
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What is the proper way to URL encode Unicode characters?
I know of the non-standard %uxxxx scheme but that doesn't seem like a wise choice since the scheme has been rejected by the W3C.
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When should I release objects in -(void)viewDidUnload rather than in -dealloc?
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As the documentation says:
It is called during low-memory conditions when the view controller needs to release its view and any objects associated with that view to free up memory.
In the same situation dealloc is not called. ...
Entity Framework: There is already an open DataReader associated with this Command
...hat is the question. Maybe there is more then one command executed but you don't see it. I'm not sure if this can be traced in Profiler (exception can be thrown before second reader is executed). You can also try to cast the query to ObjectQuery and call ToTraceString to see the SQL command. It is h...
How to merge dictionaries of dictionaries?
...accepting duplicate but consistent entries (something no other answer here does....)
assuming you don't have huge numbers of entries a recursive function is easiest:
def merge(a, b, path=None):
"merges b into a"
if path is None: path = []
for key in b:
if key in a:
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