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Using “label for” on radio buttons
When using the "label for" parameter on radio buttons, to be 508 compliant *, is the following correct?
3 Answers
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How to navigate through the source code by parts in CamelCase (instead of whole words)?
... I agree that this should be the default behavior. For anyone coming from Eclipse this is like built into our muscle memory from day one.
– Pierre
Dec 2 '15 at 21:14
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MySQL SELECT WHERE datetime matches day (and not necessarily time)
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I was about to comment that a1ex07's solution seems not near as good as the others. After reading your post, maybe I need to reverse my thinking!
– user1032531
Dec 31 '12 at 17:26
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Escape quote in web.config connection string
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Drawing a connecting line between two elements [closed]
How can I drawing a line between two or more elements to connect them? Any combination of HTML/CSS/JavaScript/SVG/Canvas is fine.
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Should I be concerned about excess, non-running, Docker containers?
Every docker run command, or every RUN command inside a Dockerfile, creates a container. If the container is no longer running it can still be seen with docker ps -a .
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View a list of recent documents in Vim
...ll be multiple listings of the same document in the list. Is there another command which would do what I'm looking for?
8 A...
How to run a single test from a rails test suite?
...n Rakefile will NOT get executed.
To run a single test, use the following command from your rails project's main directory:
ruby -I test test/unit/my_model_test.rb -n test_name
This runs a single test named "name", defined in the MyModelTest class in the specified file. The test_name is formed ...
Why can't I center with margin: 0 auto?
...ock-level
* element. It is still good to use display: inline on it to overcome a bug
* in IE6 and below that doubles horizontal margins for floated elements)
* The styles below is the full style for the list-items.
*/
#header ul li {
color:#CCCCCC;
display:inline;
font-size:20px;
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How do I calculate the normal vector of a line segment?
...ight angle lines, hence dy' = dx' * (-dx/dy) and dx' = dy' * (-dy/dx), how come in your equation normal.x = x' = -dy?
– legends2k
Jan 25 '13 at 8:53
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