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Why does `a == b or c or d` always evaluate to True?
...= "Kevin" or name == "Jon" or name == "Inbar"', setup="name='Inbar'")
0.4247764749999945
>>> timeit.timeit('name in {"Kevin", "Jon", "Inbar"}', setup="name='Inbar'")
0.18493307199999265
For those who may want proof that if a == b or c or d or e: ... is indeed parsed like this. The built-i...
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