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“A project with an Output type of Class Library cannot be started directly”
...Single Startup Project
Select your Project in there and apply.
That's it. Now save and build your project. Run the project to see the output.
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Difference between array_push() and $array[] =
...e in that way there is no overhead of calling a function." don't have time now to see exactly what is behind it as the search term is bit confusing for search engines :)
– jnhghy - Alexandru Jantea
Jun 16 '17 at 14:29
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Rails select helper - Default selected value, how?
Here is a piece of code I'm using now:
15 Answers
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laravel throwing MethodNotAllowedHttpException
I am trying to get something very basic running. I am used to CI and now learning Laravel 4, and their docs are not making it easy! Anyways, I am trying to create a login form and just make sure that data is posted successfully by printing it in the next form. I am getting this exception:
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Stop Visual Studio from launching a new browser window when starting debug?
...ect URL" and saw that it got changed in .csproj. Upon closer inspection, I now see that there is a "Apply server settings to all users" checkmark which controls just that field. My bad.
– mjohnsonengr
Mar 29 '16 at 17:06
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JSON Array iteration in Android/Java
...of JSONArray iterable, meaning that the for (Object foo : bar) syntax will now work with it (note that foo has to be an Object, because JSONArrays do not have a declared type). All this works because the JSONArray class is backed by a simple ArrayList, which is already iterable. I imagine that other...
Java ResultSet how to check if there are any results
...ately after to reset it, since it has positioned itself past the first row now.
It should be noted however, that Seifer's answer below is a more elegant solution to this question.
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Filter data.frame rows by a logical condition
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I wonder if this works now? I wasn't able to subset dataframe based on condition in this way.
– Sumanth Lazarus
Oct 10 '19 at 11:47
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Why is UICollectionViewCell's outlet nil?
...orrect (correct identifier & class) it refused to connect the outlets. now it works. sweet!
– Joris Weimar
Oct 9 '14 at 19:36
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how to break the _.each function in underscore.js
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right now (05/2013), there is neither a _.every() nor a _.all() method for arrays in underscore - so stick to the Array.every().
– pkyeck
May 9 '13 at 9:09
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