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How to format all Java files in an Eclipse project at one time?
...old Eclipse project and the code is not well formatted. I'd like to format all the .java files according to the settings in Eclipse. I don't want to edit every individual file with Ctrl + Shift + F . Is there a way to format all my files? Perhaps an Eclipse plugin?
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Get current date in milliseconds
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There are several ways of doing this, although my personal favorite is:
CFAbsoluteTime timeInSeconds = CFAbsoluteTimeGetCurrent();
You can read more about this method here. You can also create a NSDate object and get time by calling timeInterval...
Chmod recursively
...have an archive, which is archived by someone else, and I want to automatically, after I download it, to change a branch of the file system within the extracted files to gain read access. (I can't change how archive is created).
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Why are these numbers not equal?
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General (language agnostic) reason
Since not all numbers can be represented exactly in IEEE floating point arithmetic (the standard that almost all computers use to represent decimal numbers and do math with them), you will not always get what you expected. This is espe...
Backporting Python 3 open(encoding=“utf-8”) to Python 2
I have a Python codebase, built for Python 3, which uses Python 3 style open() with encoding parameter:
6 Answers
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How to get the first and last date of the current year?
Using SQL Server 2000, how can I get the first and last date of the current year?
18 Answers
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SQL query for finding records where count > 1
... a user ID, an account number, a ZIP code and a date. I would like to find all records for all users that have more than one payment per day with the same account number.
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Transpose list of lists
...npacked argument lists: Given a sequence of arguments args, f(*args) will call f such that each element in args is a separate positional argument of f.
Coming back to the input from the question l = [[1, 2, 3], [4, 5, 6], [7, 8, 9]], zip(*l) would be equivalent to zip([1, 2, 3], [4, 5, 6], [7, 8, ...
Ruby Arrays: select(), collect(), and map()
...following:
details.select{ |item| item[:qty] != "" }
That will give you all items where the :qty key isn't an empty string.
official select documentation
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Selecting only first-level elements in jquery
...; li a")
But you would need to set a class on the root ul if you specifically want to target the outermost ul:
<ul class="rootlist">
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Then it's:
$("ul.rootlist > li a")....
Another way of making sure you only have the root li elements:
$("ul > li a").not("ul li ul a")
It lo...