... | edited Jul 2 '17 at 11:42 answered Nov 20 '14 at 10:43 t...

... Chris ArguinChris Arguin 11.1k44 gold badges2828 silver badges4646 bronze badges ...

... ryenus 11.3k44 gold badges4747 silver badges5454 bronze badges answered Oct 15 '08 at 17:32 Adam CrumeAdam Crume ...

... a formula to mean all the variables, it is the . identifier. y <- c(1,4,6) d <- data.frame(y = y, x1 = c(4,-1,3), x2 = c(3,9,8), x3 = c(4,-4,-2)) mod <- lm(y ~ ., data = d) You can also do things like this, to use all variables but one (in this case x3 is excluded): mod <- lm(y ~ . ...

... feature has already been integrated into the standard draft. UPDATE 2014: C++14 has been released this year and now provides Polymorphic lambdas with the same syntax as in this example. Some major compilers already implement it. At it stands (in C++11), sadly no. Polymorphic lambdas would be ...

... 1934 Search Tables: SELECT c.name AS 'ColumnName' ,t.name AS 'TableName' FROM ...

...ding) – Mark Garcia Dec 11 '12 at 8:46 2 @MarkGarcia, This might be helpful: stackoverflow.com/qu...

... comment result in Dirk answer is not a list of lists. Is a list of length 4, which elements are language type. First object is a symbol - list, second is expression 1:10 and so on. That explain why [-1L] is needed: it removes expected symbol from provided arguments in ... (cause it is always a list...

... 294 See Function Definitions in the Language Reference. If the form *identifier is present, it...

... 413 One more solution, which works for both numeric & character/factor data: Mode <- funct...