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Can I keep Nuget on the jQuery 1.9.x/1.x path (instead of upgrading to 2.x)?
...support for several browsers should have been made into a separate version 2 nuget package and advertised accordingly, i.e. with significant disclaimers. The 1.9 library is not legacy and will receive further updates in the future. I've been in touch with the package author and will write more if I ...
Converting a list to a set changes element order
...the list, you can do this with a list comprehension:
>>> a = [1, 2, 20, 6, 210]
>>> b = set([6, 20, 1])
>>> [x for x in a if x not in b]
[2, 210]
If you need a data structure that supports both fast membership tests and preservation of insertion order, you can use the k...
【HarmonyOS】编译、测试全流程 - HarmonyOS NEXT - 清泛IT社区，为创新赋能！
...意设备可以无限制华为开发者后台(AGC)申请正式发布
1.2 与 Android/iOS 签名体系对比
维度AndroidiOSHarmonyOS NEXT未签名安装开启"未知来源"即可不允许不允许（模拟器除外）调试签名自签名APK即可需Apple开发者证书+设备注册...
Shuffle two list at once with same order
...t pre-processing. But there is problem, in lists documents and documents2 I have the same documents and I need shuffle them in order to keep same order in both lists. I cannot shuffle them separately because each time I shuffle the list, I get other results. That is why I need to shuffle the at ...
Transpose/Unzip Function (inverse of zip)?
I have a list of 2-item tuples and I'd like to convert them to 2 lists where the first contains the first item in each tuple and the second list holds the second item.
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How do I compare two hashes?
...can compare hashes directly for equality:
hash1 = {'a' => 1, 'b' => 2}
hash2 = {'a' => 1, 'b' => 2}
hash3 = {'a' => 1, 'b' => 2, 'c' => 3}
hash1 == hash2 # => true
hash1 == hash3 # => false
hash1.to_a == hash2.to_a # => true
hash1.to_a == hash3.to_a # => false
...
Finding the index of elements based on a condition using python list comprehension
...t all, but just deal with the values—[value for value in a if value > 2]. Usually dealing with indexes means you're not doing something the best way.
If you do need an API similar to Matlab's, you would use numpy, a package for multidimensional arrays and numerical math in Python which is heavi...
Remove all values within one list from another list? [duplicate]
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>>> a = range(1, 10)
>>> [x for x in a if x not in [2, 3, 7]]
[1, 4, 5, 6, 8, 9]
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How to delete multiple values from a vector?
... a vector like: a = c(1:10) and I need to remove multiple values, like: 2, 3, 5
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