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Can you use a trailing comma in a JSON object?

... 255 Unfortunately the JSON specification does not allow a trailing comma. There are a few browsers ...
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Lua string to int

... | edited Dec 16 '16 at 15:12 answered Jun 9 '12 at 15:14 ...
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Convert from ASCII string encoded in Hex to plain ASCII?

... A slightly simpler solution: >>> "7061756c".decode("hex") 'paul' share | improve this answer | follow | ...
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How to implement “select all” check box in HTML?

...each...in construct doesn't seem to work, at least in this case, in Safari 5 or Chrome 5. This code should work in all browsers: function toggle(source) { checkboxes = document.getElementsByName('foo'); for(var i=0, n=checkboxes.length;i<n;i++) { checkboxes[i].checked = source.checked; ...
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Is it possible to make the -init method private in Objective-C?

... | edited Feb 15 '13 at 15:29 jlehr 15k55 gold badges4141 silver badges4545 bronze badges ans...
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How to find the extension of a file in C#?

... JamesJames 72.6k1717 gold badges151151 silver badges216216 bronze badges 8 ...
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Numpy first occurrence of value greater than existing value

... This is a little faster (and looks nicer) np.argmax(aa>5) Since argmax will stop at the first True ("In case of multiple occurrences of the maximum values, the indices corresponding to the first occurrence are returned.") and doesn't save another list. In [2]: N = 10000 In [3...
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How to initialise memory with new operator in C++?

...seful for value initialization). This is explicitly permitted by ISO C++03 5.3.4[expr.new]/15, which says: A new-expression that creates an object of type T initializes that object as follows: ... If the new-initializer is of the form (), the item is value-initialized (8.5); and does not restric...
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Is it not possible to stringify an Error using JSON.stringify?

...hem. – user2437417 Aug 22 '13 at 21:56 8 Better not addit to the Error.prototype, can give issues...
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Working with time DURATION, not time of day

...imply 1.0 equals 1 full day (starting on 1/1/1900). So 36 hours would be 1.5. If you change the format to [h]:mm, you'll see 36:00. Therefore, if you want to work with durations, you can simply use subtraction, e.g. A1: Start: 36:00 (=1.5) A2: End: 60:00 (=2.5) A3: Duration:...