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How to get a resource id with a known resource name?
...ence using resIdByName method:
val drawableResId = context.resIdByName("ic_edit_black_24dp", "drawable")
val stringResId = context.resIdByName("title_home", "string")
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Rails DB Migration - How To Drop a Table?
...ically, you can see how to drop a table using the following approach:
drop_table :table_name
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HTML code for an apostrophe
...hat is ok according to wikipedia: en.wikipedia.org/wiki/Apostrophe#Entering_apostrophes
– matt burns
Feb 24 '15 at 10:52
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How to check certificate name and alias in keystore files?
... command will yield all aliases containing the pattern 'foo', f.e. foo, 123_FOO, fooBar, etc. For more information man grep.
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How can I use MS Visual Studio for Android Development?
...ontrol Panel > System > Advanced > Environment Variables)
ANDROID_HOME = <install_path>\android-sdk
ANDROID_NDK_ROOT = <install_path>\android-ndk
ANT_HOME = <install_path>\apache-ant
JAVA_HOME = <install_path>\jdk
_JAVA_OPTIONS = -Xms256m -Xmx512m
Download exa...
Collections.emptyList() vs. new instance
...inal <T> List<T> emptyList() {
return (List<T>) EMPTY_LIST;
}
So if your method (which returns an empty list) is called very often, this approach may even give you slightly better performance both CPU and memory wise.
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How do I read all classes from a Java package in the classpath?
...ass>();
String packageSearchPath = ResourcePatternResolver.CLASSPATH_ALL_URL_PREFIX +
resolveBasePackage(basePackage) + "/" + "**/*.class";
Resource[] resources = resourcePatternResolver.getResources(packageSearchPath);
for (Resource resource : resources...
Java / Android - How to print out a full stack trace?
... yup you're right @PhilippReichart. Here's the code for Log.d on AOSP 4.2.2_r1
– Ehtesh Choudhury
Apr 25 '13 at 17:06
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What's the role of adapters in Android?
...; adapter = new ArrayAdapter<String>(this,
android.R.layout.simple_list_item_1, android.R.id.text1, values);
First parameter: Context
Second parameter: Layout for the row
Third parameter: ID of the TextView to which the data is written
Fourth parameter: The array of data
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How do I merge two javascript objects together in ES6+?
...:
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Object/assign
Syntax:
Object.assign(target, sources);
where ...sources represents the source object(s).
Example:
var obj1 = {name: 'Daisy', age: 30};
var obj2 = {name: 'Casey'};
Object.assign(obj1, obj2);
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