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Sending Arguments To Background Worker?
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@rayray: label1.Text = e.Result.ToString(); , everywhere I marked that as safe.
– Henk Holterman
May 16 '19 at 4:57
add a comment
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Split string with multiple delimiters in Python [duplicate]
... this uses some RegEx like things as mentioned above. So trying to split a string with . will split every single character. You need to escape it. \.
– marsh
Nov 14 '16 at 15:38
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Where to put view-specific javascript files in an ASP.NET MVC application?
... class JavaScriptActionDescriptor : ActionDescriptor
{
private string actionName;
private ControllerDescriptor controllerDescriptor;
public JavaScriptActionDescriptor(string actionName, ControllerDescriptor controllerDescriptor)
{
this.actionName = ac...
What do
...case class Foo[A](a:A) { // 'A' can be substituted with any type
// getStringLength can only be used if this is a Foo[String]
def getStringLength(implicit evidence: A =:= String) = a.length
}
The implicit argument evidence is supplied by the compiler, iff A is String. You can think of it a...
Escape string for use in Javascript regex [duplicate]
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Short 'n Sweet
function escapeRegExp(string) {
return string.replace(/[.*+?^${}()|[\]\\]/g, '\\$&'); // $& means the whole matched string
}
Example
escapeRegExp("All of these should be escaped: \ ^ $ * + ? . ( ) | { } [ ]");
>>> "All of th...
How do I change the string representation of a Python class? [duplicate]
In Java, I can override the toString() method of my class. Then Java's print function prints the string representation of the object defined by its toString() . Is there a Python equivalent to Java's toString() ?
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Split string on whitespace in Python [duplicate]
...es a list of size 2. First item being the first word, second - rest of the string. s.split(None, 1)[0] would return the first word only
– user3527975
Feb 25 '16 at 21:43
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require file as string
...sing node + express and I am just wondering how I can import any file as a string. Lets say I have a txt file all I want is to load it into a variable as such.
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Django: Get model from string?
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Most model "strings" appear as the form "appname.modelname" so you might want to use this variation on get_model
from django.db.models.loading import get_model
your_model = get_model ( *your_string.split('.',1) )
The part of the djan...