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C++ “virtual” keyword for functions in derived classes. Is it necessary?
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This is true, but the Mozilla C++ Portability Guide recommends always using virtual because "some compilers" issue warnings if you don't. Too bad they don't mention any examples of such compilers.
– Sergei Tachenov
F...
C++ include and import difference
What is the difference between #include and #import in C++?
5 Answers
5
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C++ cout hex values?
...com/fYXyh6. This is permitted for ios::floatfield according to Thinking in C++ vol 2 page 189, but it doesn't say the same about ios::basefield.
– Joel Sjögren
Jul 21 '13 at 15:14
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Who architected / designed C++'s IOStreams, and would it still be considered well-designed by today'
... earlier streams library, but were authored at a time when many of today's C++ idioms didn't exist, so the designers didn't have the benefit of hindsight. One issue that only became apparent over time was that it is almost impossible to implement IOStreams as efficiently as C's stdio, due to the cop...
Convert char to int in C and C++
How do I convert a char to an int in C and C++?
12 Answers
12
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Why does fatal error “LNK1104: cannot open file 'C:\Program.obj'” occur when I compile a C++ project
I've created a new C++ project in Visual Studio 2008. No code has been written yet; Only project settings have been changed.
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Cannot find or open the PDB file in Visual Studio C++ 2010
I use Visual Studio 2010 C++ and my project builds without errors but when I run it I get this. I am on Windows XP.
7 Answe...
(-2147483648> 0) returns true in C++?
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-2147483648 is not a "number". C++ language does not support negative literal values.
-2147483648 is actually an expression: a positive literal value 2147483648 with unary - operator in front of it. Value 2147483648 is apparently too large for the positiv...
Why doesn't c++ have &&= or ||= for booleans?
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A bool may only be true or false in C++. As such, using &= and |= is relatively safe (even though I don’t particularly like the notation). True, they will perform bit operations rather than logical operations (and thus they won’t short-circuit) but thes...
My attempt at value initialization is interpreted as a function declaration, and why doesn't A a(())
...ightened answer, it's just because it's not defined as valid syntax by the C++ language... So it is so, by definition of the language.
If you do have an expression within then it is valid. For example:
((0));//compiles
Even simpler put: because (x) is a valid C++ expression, while () is not. ...