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REDHAT 6.4 X64下ORACLE 11GR2静默安装 - 数据库(内核) - 清泛网 - 专注C/C++及内核技术
...# - SEONE : Standard Edition One 标着版ONE仅许可在最高容量为两个处理器的服务器上使用，不支持集群
# - PE : Personal Edition (WINDOWS ONLY) 个人版
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oracle.install.db.InstallEditi...
Remove accents/diacritics in a string in JavaScript
...h for ł -> l).
– Paweł Fus
Jul 24 '17 at 13:23
7
...
typedef fixed length array
I have to define a 24-bit data type.I am using char[3] to represent the type. Can I typedef char[3] to type24 ? I tried it in a code sample. I put typedef char[3] type24; in my header file. The compiler did not complain about it. But when I defined a function void foo(type24 val) {} in my C...
SVG gradient using CSS
...
morkro
3,02433 gold badges2222 silver badges3434 bronze badges
answered Dec 27 '12 at 8:21
Thomas WThomas W
...
How do I add 24 hours to a unix timestamp in php?
I would like to add 24 hours to the timestamp for now. How do I find the unix timestamp number for 24 hours so I can add it to the timestamp for right now?
...
Comparing two dataframes and getting the differences
...
24
Passing the dataframes to concat in a dictionary, results in a multi-index dataframe from which...
Converting between datetime, Timestamp and datetime64
...time.utcnow()
>>> dt
datetime.datetime(2012, 12, 4, 19, 51, 25, 362455)
>>> dt64 = np.datetime64(dt)
>>> ts = (dt64 - np.datetime64('1970-01-01T00:00:00Z')) / np.timedelta64(1, 's')
>>> ts
1354650685.3624549
>>> datetime.utcfromtimestamp(ts)
datetime.date...
In Java, what is the best way to determine the size of an object?
...|
edited Jun 28 '16 at 18:24
Ravindra babu
39.4k77 gold badges201201 silver badges180180 bronze badges
a...
SQL to determine minimum sequential days of access?
...tains one record for every day a given user has accessed a website (in a 24 hour UTC period). It has many thousands of records, but only one record per day per user. If the user has not accessed the website for that day, no record will be generated.
...
How to calculate the difference between two dates using PHP?
...s it's rather easy to calculate different time periods.
$date1 = "2007-03-24";
$date2 = "2009-06-26";
$diff = abs(strtotime($date2) - strtotime($date1));
$years = floor($diff / (365*60*60*24));
$months = floor(($diff - $years * 365*60*60*24) / (30*60*60*24));
$days = floor(($diff - $years * 365*6...