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Python assigning multiple variables to same value? list behavior
...es are naming the same object, use the is operator:
>>> a=b=c=[0,3,5]
>>> a is b
True
You then ask:
what is different from this?
d=e=f=3
e=4
print('f:',f)
print('e:',e)
Here, you're rebinding the name e to the value 4. That doesn't affect the names d and f in any way.
...
Pickle incompatibility of numpy arrays between Python 2 and 3
I am trying to load the MNIST dataset linked here in Python 3.2 using this program:
7 Answers
...
Read stream twice
...
Captain Man
5,26733 gold badges3636 silver badges6161 bronze badges
answered Feb 29 '12 at 14:59
Paul GrimePaul Grime
...
Pad a string with leading zeros so it's 3 characters long in SQL Server 2008
I have a string that is up to 3 characters long when it's first created in SQL Server 2008 R2.
17 Answers
...
Plot a legend outside of the plotting area in base graphics?
...
113
Maybe what you need is par(xpd=TRUE) to enable things to be drawn outside the plot region. So if...
Is 'float a = 3.0;' a correct statement?
...
It is not an error to declare float a = 3.0 : if you do, the compiler will convert the double literal 3.0 to a float for you.
However, you should use the float literals notation in specific scenarios.
For performance reasons:
Specifically, consider:
float fo...
Removing duplicates in lists
...ample should cover whatever you are trying to do:
>>> t = [1, 2, 3, 1, 2, 5, 6, 7, 8]
>>> t
[1, 2, 3, 1, 2, 5, 6, 7, 8]
>>> list(set(t))
[1, 2, 3, 5, 6, 7, 8]
>>> s = [1, 2, 3]
>>> list(set(t) - set(s))
[8, 5, 6, 7]
As you can see from the example resu...
Why exactly is eval evil?
...tors:
(let ((ops '(+ *)))
(dolist (op ops)
(print (eval (list op 1 2 3)))))
That's better written as:
(let ((ops '(+ *)))
(dolist (op ops)
(print (funcall op 1 2 3))))
There are lots of examples where beginners learning Lisp think they need EVAL, but they don't need it - since expressi...
jQuery map vs. each
...you can potentially waste a lot of memory.
For example:
var items = [1,2,3,4];
$.each(items, function() {
alert('this is ' + this);
});
var newItems = $.map(items, function(i) {
return i + 1;
});
// newItems is [2,3,4,5]
You can also use the map function to remove an item from an array. F...