大约有 48,000 项符合查询结果（耗时：0.0615秒） [XML]
Logic to test that 3 of 4 are True
...
Not sure it is simpler, but maybe.
((x xor y) and (a and b)) or ((x and y) and (a xor b))
share
|
improve this answer
|
follow
...
cpuid汇编指令 - C/C++ - 清泛网 - 专注C/C++及内核技术
...puid指令cpuid就是一条读取CPU各种信息的一条指令，大概是从80486的某个版本开始就存在了。 CPUID这条指令，除了用于识别CPU（CPU的型号...cpuid指令
cpuid就是一条读取CPU各种信息的一条指令，大概是从80486的某个版本开始就存在...
Easiest way to flip a boolean value?
...han longVariableName = !longVariableName; And every programmer should know XOR.
– xamid
Oct 5 '17 at 16:15
3
...
What is the fastest way to compare two sets in Java?
...like that? Well if the set hashcode was:
zero for an empty set, and
the XOR of all of the element hashcodes for a non-empty set,
then you could cheaply update the set's cached hashcode each time you added or removed an element. In both cases, you simply XOR the element's hashcode with the curr...
Best practices for overriding isEqual: and hash
...
A simple XOR over the hash values of critical properties is sufficient
99% of the time.
For example:
- (NSUInteger)hash
{
return [self.name hash] ^ [self.data hash];
}
Solution found at http://nshipster.com/equality/ by Mat...
boost多索引容器multi_index_container实战 - C/C++ - 清泛网 - 专注C/C++及内核技术
...iner,Tag>::type& i = get<Tag>(s);这段代码定义了一个容器索引，从容器s中提取出Tag标签作为索引的序列i（对于有序的容器也可以说是用Tag排序的序列），接下来是typedef typename MultiIndexContainer::value_type value_type;语句定义了容器的元素类...
CMake使用教程 - C/C++ - 清泛网 - 专注C/C++及内核技术
...roj项目。
通过编写CMakeLists.txt，可以控制生成的Makefile，从而控制编译过程。CMake自动生成的Makefile不仅可以通过make命令构建项目生成目标文件，还支持安装（make install）、测试安装的程序是否能正确执行（make test，或者ctest）...
Random shuffling of an array
...
The xor trick is great for swapping CPU registers when the CPU has no swap instruction and there are no free registers, but for swapping array elements inside a loop, I don’t see any benefit. For the temporary local variables, ...
20个命令行工具监控 Linux 系统性能 - 更多技术 - 清泛网 - 专注C/C++及内核技术
...包括 Apache、MYSQL、Mail、FTP、Nginx 等等。系统状态是可以从命令行或者自己的网络接口来查看。
12. NetHogs — 监视每个进程的网络带宽
NetHogs 是一个开源的漂亮的小程序（类似于 Linux 上面的 top 命令），在您的系统上保持每个进...
For i = 0, why is (i += i++) equal to 0?
...
Disassembly of the running code:
int i = 0;
xor edx, edx
mov dword ptr i, edx // set i = 0
i += i++;
mov eax, dword ptr i // set eax = i (=0)
mov dword ptr tempVar1, eax // set tempVar1 = eax (=0)
mov eax...