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How to display request headers with command line curl
Command line curl can display response header by using -D option, but I want to see what request header it is sending. How can I do that?
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Is it okay to use now?
...adjust the keyboard for the user, but I'm worried about breaking backwards compatibility. What I'm hoping is that browsers/phone that support this can assist the user and other browser will fall back to a standard text field? Is this an acceptable practice? Does it even work?
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Webview load html from assets directory
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Git Ignores and Maven targets
...ore patterns do not seem to be applied recursively. See also stackoverflow.com/questions/971465/… .
– VonC
Jun 14 '09 at 13:45
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How to resize the AVD emulator (in Eclipse)?
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According to developer.android.com/studio/run/emulator-commandline -scale option is deprecated
– ViliusK
Sep 19 '18 at 11:27
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Can I find out the return value before returning while debugging in Visual Studio?
... I know of. Note that if you do add a variable, it will get removed by the compiler in release builds anyway...
Update:
This functionality has been added to VS2013.
You can see the return values in the autos windows or use $ReturnValue in the watch/immediate window.
The value can only be seen dire...
Need command line to start web browser using adb
How can I start a browser with the adb shell command and make it open a certain web page?
5 Answers
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How to add System.Windows.Interactivity to project?
...ity . Google says that I have to install Expression Blend, but on my other computer I have this library and I don't have Expression Blend installed. So there should be another way to obtain System.Windows.Interactivity ? What should I do? (right now i don't have another computer so I can not just c...
Facebook access token server-side validation for iPhone app
I'm developing iPhone application, that is based on communication with server, and I want to use Facebook authentication mechanisms.
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Iterate all files in a directory using a 'for' loop
...the current directory:
for /r %i in (*) do echo %i
Also if you run that command in a batch file you need to double the % signs.
for /r %%i in (*) do echo %%i
(thanks @agnul)
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