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Which C++ idioms are deprecated in C++11?
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Final Class: C++11 provides the final specifier to prevent class derivation
C++11 lambdas substantially reduce the need for named function object (functor) classes.
Move Constructor: The magical ways in which std::auto_ptr works are no lo...
Forward declaration of a typedef in C++
...o forward declare a C-style struct that was defined using typedef, in some c++ code, I have found a solution that goes as follows...
// a.h
typedef struct _bah {
int a;
int b;
} bah;
// b.h
struct _bah;
typedef _bah bah;
class foo {
foo(bah * b);
foo(bah b);
bah * mBah;
};
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How do I declare a 2d array in C++ using new?
...t will create an array of an allocated-type int[X][Y]. This is a "hole" in C++'s type system, since the ordinary type system of C++ doesn't have array dimensions with sizes not known at compile time, thus these are called "allocated types"
– Johannes Schaub - litb
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What techniques can be used to speed up C++ compilation times?
What techniques can be used to speed up C++ compilation times?
27 Answers
27
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Conveniently Declaring Compile-Time Strings in C++
Being able to create and manipulate strings during compile-time in C++ has several useful applications. Although it is possible to create compile-time strings in C++, the process is very cumbersome, as the string needs to be declared as a variadic sequence of characters, e.g.
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Benchmarking (python vs. c++ using BLAS) and (numpy)
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I've run your benchmark. There is no difference between C++ and numpy on my machine:
Do you think my approach is fair, or are there some unnecessary overheads I can avoid?
It seems fair due to there is no difference in results.
Would you expect that the result would sh...
Linux c++ error: undefined reference to 'dlopen'
I work in Linux with C++ (Eclipse), and want to use a library.
Eclipse shows me an error:
10 Answers
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Is inline assembly language slower than native C++ code?
I tried to compare the performance of inline assembly language and C++ code, so I wrote a function that add two arrays of size 2000 for 100000 times. Here's the code:
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Fast ceiling of an integer division in C / C++
Given integer values x and y , C and C++ both return as the quotient q = x/y the floor of the floating point equivalent. I'm interested in a method of returning the ceiling instead. For example, ceil(10/5)=2 and ceil(11/5)=3 .
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How do I get the type of a variable?
In C++, how does one find the type of a variable?
10 Answers
10
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