大约有 47,000 项符合查询结果(耗时:0.0352秒) [XML]
Searching for UUIDs in text with regex
...tly I'm relying on the assumption that all UUIDs will follow a patttern of 8-4-4-4-12 hexadecimal digits.
16 Answers
...
What is the difference between Ruby 1.8 and Ruby 1.9
I'm not clear on the differences between the "current" version of Ruby (1.8) and the "new" version (1.9). Is there an "easy" or a "simple" explanation of the differences and why it is so different?
...
Find the max of two or more columns with pandas
...
185
You can get the maximum like this:
>>> import pandas as pd
>>> df = pd.DataF...
JavaScript function similar to Python range()
...
89
No, there is none, but you can make one.
JavaScript's implementation of Python's range()
Tryi...
How to hash a string into 8 digits?
Is there anyway that I can hash a random string into a 8 digit number without implementing any algorithms myself?
4 Answers...
Index all *except* one item in python
... without the 3rd element:
a = range(10)[::-1] # [9, 8, 7, 6, 5, 4, 3, 2, 1, 0]
b = [x for i,x in enumerate(a) if i!=3] # [9, 8, 7, 5, 4, 3, 2, 1, 0]
This is very general, and can be used with all iterables, including numpy arrays. If you replace [] with (), b will be an i...
Delete files older than 3 months old in a directory using .NET
...
18 Answers
18
Active
...
Error installing libv8: ERROR: Failed to build gem native extension
...
try this one:
gem install libv8 -v '3.16.14.3' -- --with-system-v8
Note : Because libv8 is the interface for the V8 engine used by therubyracer,
you may need to use libv8, even if you have V8 installed already. If
you wish to use your own V8 ins...
How to get device make and model on iOS?
...
558
EITHER try this library: http://github.com/erica/uidevice-extension/ (by Erica Sadun). (The libr...
Splitting a list into N parts of approximately equal length
...Testing:
>>> chunkIt(range(10), 3)
[[0, 1, 2], [3, 4, 5], [6, 7, 8, 9]]
>>> chunkIt(range(11), 3)
[[0, 1, 2], [3, 4, 5, 6], [7, 8, 9, 10]]
>>> chunkIt(range(12), 3)
[[0, 1, 2, 3], [4, 5, 6, 7], [8, 9, 10, 11]]
...
