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Difference between `set`, `setq`, and `setf` in Common Lisp?
...st the SET function.
What is now written as:
(setf (symbol-value '*foo*) 42)
was written as:
(set (quote *foo*) 42)
which was eventually abbreviavated to SETQ (SET Quoted):
(setq *foo* 42)
Then lexical variables happened, and SETQ came to be used for assignment to them too -- so it was no ...
Java synchronized static methods: lock on object or class
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Ravindra babu
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answered Jan 13 '09 at 0:53
OscarRyzOscarRyz...
What is “git remote add …” and “git push origin master”?
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answered Apr 11 '11 at 6:04
Noufal IbrahimNoufal Ibrahim
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List comprehension: Returning two (or more) items for each item
...gt; list(chain.from_iterable((f(x), g(x)) for x in range(3)))
[2, 0, 3, 1, 4, 4]
Timings:
from timeit import timeit
f = lambda x: x + 2
g = lambda x: x ** 2
def fg(x):
yield f(x)
yield g(x)
print timeit(stmt='list(chain.from_iterable((f(x), g(x)) for x in range(3)))',
setu...
Memoization in Haskell?
... `div` 2) +
mf (n `div` 3) +
mf (n `div` 4)
You can get an unmemoized f by using fix f
This will let you test that f does what you mean for small values of f by calling, for example: fix f 123 = 144
We could memoize this by defining:
f_list :: [Int]
f_list = m...
PHP append one array to another (not array_push or +)
...
436
array_merge is the elegant way:
$a = array('a', 'b');
$b = array('c', 'd');
$merge = array_me...
Replacing a 32-bit loop counter with 64-bit introduces crazy performance deviations with _mm_popcnt_
...a very weird effect: Changing the loop variable from unsigned to uint64_t made the performance drop by 50% on my PC.
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What Process is using all of my disk IO
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edited Dec 7 '14 at 14:13
Aaron Digulla
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【内核源码】linux UDP实现 - 操作系统(内核) - 清泛网 - 专注C/C++及内核技术
... .owner = THIS_MODULE,
.close = udp_lib_close,
.connect = ip4_datagram_connect,
.disconnect = udp_disconnect,
.ioctl = udp_ioctl,
.destroy = udp_destroy_sock,
.setsockopt = udp_setsockopt,
.getsockopt = udp_getsockopt,
.sendmsg = udp_sendmsg,
.recvmsg ...
Insert an element at a specific index in a list and return the updated list
... do b = a[:index] + [obj] + a[index:].
However, another way is:
a = [1, 2, 4]
b = a[:]
b.insert(2, 3)
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