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How to find and return a duplicate value in array
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a = ["A", "B", "C", "B", "A"]
a.detect{ |e| a.count(e) > 1 }
I know this isn't very elegant answer, but I love it. It's beautiful one liner code. And works perfectly fine unless you need to process huge data set.
Looking for faster solution? Here you go!
def find_one_using_h...
How to print color in console using System.out.println?
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13 Answers
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What is the best way to get all the divisors of a number?
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16 Answers
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What regular expression will match valid international phone numbers?
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\+(9[976]\d|8[987530]\d|6[987]\d|5[90]\d|42\d|3[875]\d|
2[98654321]\d|9[8543210]|8[6421]|6[6543210]|5[87654321]|
4[987654310]|3[9643210]|2[70]|7|1)\d{1,14}$
Is the correct format for matching a generic international phone number. I replaced the US land line centric international access c...
How to modify a global variable within a function in bash?
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edited Oct 2 '18 at 16:01
kvantour
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How do I parse command line arguments in Bash?
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How to trace the path in a Breadth-First Search?
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197
+50
You sho...
How to calculate date difference in JavaScript?
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18 Answers
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Split column at delimiter in data frame [duplicate]
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105
@Taesung Shin is right, but then just some more magic to make it into a data.frame.
I added a ...
Extract a substring according to a pattern
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Here are a few ways:
1) sub
sub(".*:", "", string)
## [1] "E001" "E002" "E003"
2) strsplit
sapply(strsplit(string, ":"), "[", 2)
## [1] "E001" "E002" "E003"
3) read.table
read.table(text = string, sep = ":", as.is = TRUE)$V2
## [1] "E001" "E002...