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Patterns for handling batch operations in REST web services?

...ce. For example, to delete several messages at once. DELETE /mail?&id=0&id=1&id=2 It's a little more complicated to batch update partial resources, or resource attributes. That is, update each markedAsRead attribute. Basically, instead of treating the attribute as part of each resourc...
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Get __name__ of calling function's module in Python

...ef info(msg): frm = inspect.stack()[1] mod = inspect.getmodule(frm[0]) print '[%s] %s' % (mod.__name__, msg) share | improve this answer | follow ...
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Difference between `mod` and `rem` in Haskell

... 20 I had the same question about rem and mod in Clojure, and this was the answer. – noahlz Jul 11 '12 at...
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Is there a way to rename an Xcode 4 scheme?

... | edited Mar 18 '11 at 0:59 answered Mar 18 '11 at 0:54 ...
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What does template mean?

...Factorial<N - 1>::value }; }; template <> struct Factorial<0> { enum { value = 1 }; }; // Factorial<4>::value == 24 // Factorial<0>::value == 1 void foo() { int x = Factorial<4>::value; // == 24 int y = Factorial<0>::value; // == 1 } ...
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Pandas aggregate count distinct

... How about either of: >>> df date duration user_id 0 2013-04-01 30 0001 1 2013-04-01 15 0001 2 2013-04-01 20 0002 3 2013-04-02 15 0002 4 2013-04-02 30 0002 >>> df.groupby("date").agg({"duration": np.sum, "user_id...
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Fixed point vs Floating point number

...d represent would be 99999.99999 and the smallest non-zero number would be 00000.00001. Every bit of code that processes such numbers has to have built-in knowledge of where the decimal point is. A floating point number does not reserve a specific number of bits for the integer part or the fraction...
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SQL query for today's date minus two months

... 290 If you are using SQL Server try this: SELECT * FROM MyTable WHERE MyDate < DATEADD(month, -2...
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Can't resize UIView in IB

... | edited Jul 6 '09 at 15:50 answered Jul 6 '09 at 15:44 ...
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What is the most efficient way to create a dictionary of two pandas Dataframe columns?

...Speed comparion (using Wouter's method) In [6]: df = pd.DataFrame(randint(0,10,10000).reshape(5000,2),columns=list('AB')) In [7]: %timeit dict(zip(df.A,df.B)) 1000 loops, best of 3: 1.27 ms per loop In [8]: %timeit pd.Series(df.A.values,index=df.B).to_dict() 1000 loops, best of 3: 987 us per loop...