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How can I open a Shell inside a Vim Window?
...y horizontal splits without a patch) to split your terminal. But I do not know the way to have one instance of Vim in both panes.
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Get value of a string after last slash in JavaScript
...
When I know the string is going to be reasonably short then I use the following one liner... (remember to escape backslashes)
// if str is C:\windows\file system\path\picture name.jpg
alert( str.split('\\').pop() );
alert pops up ...
深入理解 x86/x64 的中断体系 - 操作系统(内核) - 清泛网 - 专注C/C++及内核技术
...T_SEG
;----------------------------------------------------------
; Now, the processor is real mode
;----------------------------------------------------------
bits 16
org BOOT_SEG ; for int 19
start:
mov ax, cs
mov ds,...
Combining “LIKE” and “IN” for SQL Server [duplicate]
... I was looking for regex example inside the like but this will do for now !
– Pini Cheyni
Mar 24 '16 at 9:29
You ...
Auto-indent in Notepad++
...munity wiki
3 revs, 2 users 60%unknown
2
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Read environment variables in Node.js
...he top of your application entry file:
require('dotenv').config();
Done. Now you can access your environment variables with process.env.ENV_NAME.
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What is the strict aliasing rule?
...wn convenience. Anyway undefined behavior might still ensue. Even when we know some of what's happening under the hood, it's still a violation of the rule so no well defined behavior is guaranteed. So just by wrapping in a function that takes our word delimited buffer doesn't necessarily help.
So ho...
How do I make my string comparison case insensitive?
...) {
System.out.println("hai");
} else {
System.out.println("welcome");
}
Now it will output : hai
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Rethrowing exceptions in Java without losing the stack trace
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In Java 7 compiler for such rethrow is more inteligent. Now it works fine with specific "throws" exceptions in containing method.
– Waldemar Wosiński
Jan 29 '13 at 16:18
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How does the C code that prints from 1 to 1000 without loops or conditional statements work?
...ds down to 0 for all j < 1000; once j reaches 1000, it evaluates to 1.
Now if you have a + (b - a) * n, where n is either 0 or 1, you end up with a if n == 0, and b if n == 1. Using &main (the address of main()) and &exit for a and b, the term (&main + (&exit - &main) * (j/10...
