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StringUtils 字符串工具扩展：强大的文本处理工具集 · App Inventor 2 中文网
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Detect iPad users using jQuery?
...ption is incorrect as iOS apps can and do customize their user agent. The main offender here is Facebook.
Compare these user agent strings from iOS devices:
# iOS Safari
iPad: Mozilla/5.0 (iPad; CPU OS 5_1 like Mac OS X) AppleWebKit/534.46 (KHTML, like Gecko) Version/5.1 Mobile/9B176 Safari/7534.4...
How can I concatenate two arrays in Java?
...files where some of the facilities like those mentioned by Antti are not available.
– kvn
Feb 7 '11 at 15:46
4
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DaffyMenu 扩展：弹出菜单扩展，为组件添加弹出式菜单功能 · App Inventor 2 中文网
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通过 ulimit 改善系统性能 - 操作系统(内核) - 清泛网 - 专注C/C++及内核技术
...rver 发出请求，那么此时 server 就会需要创建大量的 socket 连接。但在一个系统当中，往往需要限制单个 server 程序所能使用的最大 socket 数，以供其他的 server 程序所使用。那么我们如何来做到这一点呢？答案是我们可以通过 ulimi...
How to find the kth largest element in an unsorted array of length n in O(n)?
... i)
If i > k, return Select(G, n-k, i-k)
It's also very nicely detailed in the Introduction to Algorithms book by Cormen et al.
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Multiprocessing: How to use Pool.map on a function defined in a class?
...or p in proc]
return [p.recv() for (p, c) in pipe]
if __name__ == '__main__':
print parmap(lambda x: x**x, range(1, 5))
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Defeating a Poker Bot
...
classify rogue cheating or robotic
players.
Back when online poker was a fairly
new entity, there was rumour and talk with limited evidence that
some poker client software
screen-shots of suspicious players
desktops to see if they were running
programs that assist them. However (even if this were ...
What algorithms compute directions from point A to point B on a map?
...tion, you can have several layers of map data: A 'highways' layer that contains only highways, a 'secondary' layer that contains only secondary streets, and so forth. Then, you explore only smaller sections of the more detailed layers, expanding as necessary. Obviously this description leaves out a ...
How do you get the magnitude of a vector in Numpy?
...
numpy.linalg.norm contains safeguards against overflow that this implementation skips. For instance, try computing the norm of [1e200, 1e200]. There is a reason if it is slower...
– Federico Poloni
May 9 '18 ...