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plot a circle with pyplot
...dited Jul 21 '18 at 16:00
Seanny123
5,70277 gold badges4949 silver badges100100 bronze badges
answered Mar 21 '15 at 14:51
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How to make my font bold using css?
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David WoleverDavid Wolever
123k7676 gold badges297297 silver badges462462 bronze badges
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How to get last key in an array?
... such as this one should do the trick :
$array = array(
'first' => 123,
'second' => 456,
'last' => 789,
);
end($array); // move the internal pointer to the end of the array
$key = key($array); // fetches the key of the element pointed to by the internal pointer
var_...
Split comma-separated strings in a column into separate rows
...me number of strings. i.e. data.table(id= "X21", a = "chr1;chr1;chr1", b="123;133;134",c="234;254;268") becoming data.table(id = c("X21","X21",X21"), a=c("chr1","chr1","chr1"), b=c("123","133","134"), c=c("234","254","268")) ?
– Reilstein
Jan 19 '19 at 1:39
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Which terminal command to get just IP address and nothing else?
...ou know the interface, you could use:
~$ ipconfig getifaddr en0
192.168.1.123
which will return just the IP address.
Or you could loop over possible interface names, starting with a suffix, i.e. en:
for NUMBER in $(seq 0 5); do
ip=`ipconfig getifaddr en$NUMBER`
if [ -n "$ip" ]; then
...
How to use background thread in swift?
...
123
The best practice is to define a reusable function that can be accessed multiple times.
REUSA...
How can I select an element with multiple classes in jQuery?
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123
For the case
<element class="a">
<element class="b c">
</element>
</...
Convert String to SecureString
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"The combination is 12345... that's the kind of thing an idiot has on his luggage!"
– Kolob Canyon
Sep 27 '17 at 23:47
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Cookie overflow in rails application?
... :mem_cache_store, 'localhost', '127.0.0.1:11211',
{:namespace => 'myapp123'}
share
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write a shell script to ssh to a remote machine and execute commands
... -S apt-get install vlc"
HOSTS=("192.168.1.121" "192.168.1.122" "192.168.1.123")
USERNAMES=("username1" "username2" "username3")
PASSWORDS=("password1" "password2" "password3")
for i in ${!HOSTS[*]} ; do
echo ${HOSTS[i]}
SCR=${SCRIPT/PASSWORD/${PASSWORDS[i]}}
sshpass -p ${PASSWORDS[i]...