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Getting key with maximum value in dictionary?
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edited Feb 22 '18 at 17:51
Priyanka Chaudhary
63044 silver badges1111 bronze badges
answered N...
Why does [5,6,8,7][1,2] = 8 in JavaScript?
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388
[1,2,3,4,5,6][1,2,3];
^ ^
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array + — array subscript...
Replace values in list using Python [duplicate]
...want, but it doesn't actually save time:
items = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
for index, item in enumerate(items):
if not (item % 2):
items[index] = None
Here are (Python 3.6.3) timings demonstrating the non-timesave:
In [1]: %%timeit
...: items = [0, 1, 2, 3, 4, 5, 6, 7, 8,...
Version of SQLite used in Android?
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482
UPDATE OCT 2016: Here is a link to the updated official docs which includes the main points in ...
莱昂氏unix源代码分析 PDF - 文档下载 - 清泛网 - 专注C/C++及内核技术
...、文件系统、管道 133
第五部分 面向字符的特殊文件 181
下篇 莱昂氏UNIX源代码分析
前言 207
第1章 绪论 209
1.1 UNIX操作系统 209
1.2 公用程序 209
1.3 其他文档 210
1.4 UNIX程序员手册 210
1.5 UNIX文档 211
1.6 UNIX操作系...
What is the ultimate postal code and zip regex?
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TrebTreb
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What are the mathematical/computational principles behind this game?
...t 55 is more round number than 57 and left 2 cards out.
We also get n+1 = 8, so from every point (card), 8 lines pass (8 pictures appear) and every line (picture) has 8 points (appears in 8 cards).
Here's a representation of the most famous finite projective (order-2) plane (geometry) with 7 p...
Finding local IP addresses using Python's stdlib
How can I find local IP addresses (i.e. 192.168.x.x or 10.0.x.x) in Python platform independently and using only the standard library?
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Pelican 3.3 pelican-quickstart error “ValueError: unknown locale: UTF-8”
...asically, add some lines to your ~/.bash_profile:
export LC_ALL=en_US.UTF-8
export LANG=en_US.UTF-8
There is an outstanding bug report related to this issue. It appears that Python makes some assumptions about the format of locale names that aren't universally valid. Explicitly setting these en...
Get the Row(s) which have the max count in groups using groupby
... 3
1 MM1 S1 n 2
2 MM1 S3 cb 5
3 MM2 S3 mk 8
4 MM2 S4 bg 10
5 MM2 S4 dgd 1
6 MM4 S2 rd 2
7 MM4 S2 cb 2
8 MM4 S2 uyi 7
In [2]: df.groupby(['Mt'], sort=False)['count'].max()
Out[2]:
Mt
S1 3
S3 8
S4 10
S2 7
N...