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Get a random item from a JavaScript array [duplicate]
... not a valid substitution for Math.floor. Using round would cause accidentally referencing an undefined index, say in the case Math.random() is 0.95 and items.length is 5. Math.round(0.95*5) is 5, which would be an invalid index. floor(random) will always be zero in your example.
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How to check if a file exists in Go?
... You could use os.IsExist() depending the case, could be more idiomatically instead of making a double negation when doing !os.IsNotExistant()
– Ariel Monaco
Feb 17 at 3:18
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Android Game Keeps Getting Hacked [closed]
... daily who's doing the hacking. So far, we have implemented the licensing service as Google has suggested, our salt is randomly made each time the license is initiated with the unique device ID. We run the check service once, when the application is started for the first time. We then generate a ...
Django templates: verbose version of a choice
... (universal), though - unless you know a way to iterate in a template over all get_FOO_display methods of a model object :) I'm a bit too lazy for writing non-generic templates ;) Moreover, the docs say it's a model instance's method. Therefore it'd have to be a model form bound to an existing obj...
how to configure apache server to talk to HTTPS backend server?
...e, and error occured when I try to access http mode. So changing http://my-service to https://my-service helped.
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Check if two unordered lists are equal [duplicate]
...has a built-in datatype for an unordered collection of (hashable) things, called a set. If you convert both lists to sets, the comparison will be unordered.
set(x) == set(y)
Documentation on set
EDIT: @mdwhatcott points out that you want to check for duplicates. set ignores these, so you need ...
Sending email with PHP from an SMTP server
...s super useful if you're trying to connect an existing application to mail services like sendgrid or mandrill without modifying the application.
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Pythonic way to check if a list is sorted or not
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Actually we are not giving the answer anijhaw is looking for. Here is the one liner:
all(l[i] <= l[i+1] for i in xrange(len(l)-1))
For Python 3:
all(l[i] <= l[i+1] for i in range(len(l)-1))
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Check list of words in another string [duplicate]
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@Ockonal: and if you want to check that all words from that list are inside the string, just replace any() above with all()
– Nas Banov
Jul 17 '10 at 23:23
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Is That REST API Really RPC? Roy Fielding Seems to Think So
...rface", what you document is a media type, independently of your server or service.
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