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Captured variable in a loop in C#
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answered Nov 7 '08 at 7:32
Jon SkeetJon Skeet
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What Automatic Resource Management alternatives exist for Scala?
...Reader(new FileReader("file.txt"))) { reader =>
Iterator.unfold(())(_ => Option(reader.readLine()).map(_ -> ())).toList
}
or using Using.resource avoid Try
val lines: Seq[String] =
Using.resource(new BufferedReader(new FileReader("file.txt"))) { reader =>
Iterator.unfold((...
How to achieve function overloading in C?
...rt for function overloading (not operators), thanks to the addition of the _Generic keyword in C11. (supported in GCC since version 4.9)
(Overloading isn't truly "built-in" in the fashion shown in the question, but it's dead easy to implement something that works like that.)
_Generic is a compile-...
Java: Date from unix timestamp
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user136036
5,61433 gold badges3232 silver badges3535 bronze badges
answered Jul 11 '14 at 17:49
michamicha
4...
Accessing Object Memory Address
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edited Sep 23 '08 at 15:32
answered Sep 23 '08 at 14:49
A...
What's the easiest way to escape HTML in Python?
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Max Egger
322 bronze badges
answered Jun 30 '09 at 4:18
nosklonosklo
183k5252 gold badge...
Foreign keys in mongo?
... Ben
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answered Sep 5 '13 at 13:23
ZAkyZAky
82255 silver badges191...
Generate a heatmap in MatPlotLib using a scatter data set
...data
x = np.random.randn(1000)
y = np.random.randn(1000)
sigmas = [0, 16, 32, 64]
for ax, s in zip(axs.flatten(), sigmas):
if s == 0:
ax.plot(x, y, 'k.', markersize=5)
ax.set_title("Scatter plot")
else:
img, extent = myplot(x, y, s)
ax.imshow(img, extent=ext...
How do I read the contents of a Node.js stream into a string variable?
...INVALID_ARG_TYPE]: The "list[0]" argument must be an instance of Buffer or Uint8Array. Received type string if the stream produces string chunks instead of Buffer. Using chunks.push(Buffer.from(chunk)) should work with both string and Buffer chunks.
– Andrei LED
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How is Math.Pow() implemented in .NET Framework?
...rsion from Henry Warren's Hacker's Delight:
public static int iexp(int a, uint b) {
int y = 1;
while(true) {
if ((b & 1) != 0) y = a*y;
b = b >> 1;
if (b == 0) return y;
a *= a;
}
}
He notes that this operation is optimal (does the minimu...