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Wolfram's Rule 34 in XKCD [closed]
The hover "joke" in #505 xkcd touts "I call rule 34 on Wolfram's Rule 34".
12 Answers
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Oracle “(+)” Operator
..."adding NULL values if no match found". For example, "a.id=b.id(+)" means allow b.id to be NULL if there is no match with a.id.
– beach
Oct 26 '10 at 5:00
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计算统计特征（正态分布）函数及实例 - C/C++ - 清泛网 - 专注C/C++及内核技术
...AX_VAR;
double _ave;
//double _var;
double _sam_stdev;
double _all_stdev;
double _sum;
double _sum_2;
int _count;
double _min_v;
double _max_v;
StdevInfo()
: _ave(0.0)
//, _var(MAX_VAR)
, _sam_stdev(sqrt(MAX_VAR))
, _all_stdev(0.0)
, _sum(0.0)
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How do I spool to a CSV formatted file using SQLPLUS?
...tion on IDs)
spool myfile.csv
select table_name, tablespace_name
from all_tables
where owner = 'SYS'
and tablespace_name is not null;
Output will be like:
TABLE_PRIVILEGE_MAP ,SYSTEM
SYSTEM_PRIVILEGE_MAP ,SYSTEM
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Passing variable number of arguments around
...I have a C function which takes a variable number of arguments: How can I call another function which expects a variable number of arguments from inside of it, passing all the arguments that got into the first function?
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LINQ Select Distinct with Anonymous Types
...on of objects. The exact type isn't important. From it I want to extract all the unique pairs of a pair of particular properties, thusly:
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Pandas selecting by label sometimes return Series, sometimes returns DataFrame
...answered Dec 4 '13 at 19:36
Dan AllanDan Allan
27.4k66 gold badges6060 silver badges6060 bronze badges
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How to terminate a Python script
...ed by raising the
SystemExit exception, so cleanup actions specified by finally clauses
of try statements are honored, and it is possible to intercept the
exit attempt at an outer level.
The optional argument arg can be an integer giving the exit status
(defaulting to zero), or another type of obj...
Why are all fields in an interface implicitly static and final?
I am just trying to understand why all fields defined in an Interface are implicitly static and final . The idea of keeping fields static makes sense to me as you can't have objects of an interface but why they are final (implicitly)?
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JavaScript Regular Expression Email Validation [duplicate]
...
If you define your regular expression as a string then all backslashes need to be escaped, so instead of '\w' you should have '\\w'.
Alternatively, define it as a regular expression:
var pattern = /^\w+@[a-zA-Z_]+?\.[a-zA-Z]{2,3}$/;
BTW, please don't validate email address...